Question 10 - NCERT Exemplar - MCQs - Chapter 6 Class 12 Application of Derivatives

Last updated at December 16, 2024 by

If x is real, the minimum value of x 2 ā€“ 8x + 17 is

(A)ā€“1Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  (B) 0

(C) 1Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā (D) 2

Ā 

This question is similar to Ex 6.5, 1 (i) - Chapter 6 Class 12 - Application of Derivatives

If x is real, the minimum value of x2 ā€“ 8x + 17 is - Teachoo Class 12 - NCERT Exemplar - MCQs

part 2 - Question 10 - NCERT Exemplar - MCQs - Serial order wise - Chapter 6 Class 12 Application of Derivatives
part 3 - Question 10 - NCERT Exemplar - MCQs - Serial order wise - Chapter 6 Class 12 Application of Derivatives

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Question 10 If x is real, the minimum value of x2 ā€“ 8x + 17 is ā€“1 (B) 0 (C) 1 (D) 2 š‘“(š‘„) =š‘„^2āˆ’8š‘„+17 Finding š’‡^ā€² (š’™) š’‡^ā€² (š’™)=2š‘„āˆ’8+0 š‘“^ā€² (š‘„)=2š‘„āˆ’8 š‘“ā€²(š‘„)=šŸ(š’™āˆ’šŸ’) Putting fā€™ (š’™)=šŸŽ 2(š‘„āˆ’4)=0 (š‘„āˆ’4)=0 š’™=šŸ’ Thus, x = 4 is the minima Finding Minimum value š‘“(š‘„) =š‘„^2āˆ’8š‘„+17 Putting š‘„ =4 f(šŸ’)=4^2āˆ’8(4)+17 =16āˆ’32+17 =33āˆ’32 =šŸ Hence, minimum value of š‘“(š‘„) is 1. So, the correct answer is (C)

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