If x is real, the minimum value of x 2 – 8x + 17 is
(A)–1 (B) 0
(C) 1 (D) 2
This question is similar to Ex 6.5, 1 (i) - Chapter 6 Class 12 - Application of Derivatives
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NCERT Exemplar - MCQs
Last updated at April 16, 2024 by Teachoo
This question is similar to Ex 6.5, 1 (i) - Chapter 6 Class 12 - Application of Derivatives
Question 10 If x is real, the minimum value of x2 â 8x + 17 is â1 (B) 0 (C) 1 (D) 2 đ(đĽ) =đĽ^2â8đĽ+17 Finding đ^Ⲡ(đ) đ^Ⲡ(đ)=2đĽâ8+0 đ^Ⲡ(đĽ)=2đĽâ8 đâ˛(đĽ)=đ(đâđ) Putting fâ (đ)=đ 2(đĽâ4)=0 (đĽâ4)=0 đ=đ Thus, x = 4 is the minima Finding Minimum value đ(đĽ) =đĽ^2â8đĽ+17 Putting đĽ =4 f(đ)=4^2â8(4)+17 =16â32+17 =33â32 =đ Hence, minimum value of đ(đĽ) is 1. So, the correct answer is (C)