Question 5
The point on the curve y2 = x, where the tangent makes an angle of π/4 with x-axis is
(A) (1/2, 1/4) (B) (1/4, 1/2)
(C) (4, 2) (D) (1, 1)
π¦^2=π₯
Slope of the tangent is π π/π π
Finding π π/π π
2y ππ¦/ππ₯=1
π π/π π=π/ππ
Since, the tangent makes an angle of π/4 with x-axis
i.e., π½=π /π
β΄ Slope of tangent =πππ π½
=tanβ‘γπ/4γ
=π
Equating (1) and (2)
π/ππ=π
1=2π¦
2π¦=1
π=π/π
Since, we have to find point on the curve where the tangent makes an angle of π/4 with x-axis
Finding π by putting π=π/π in equation of curve
π^π=π
(π/π)^2=π₯
1/4 =π₯
π=π/π
β΄ Required point = (x, y) = (π/π,π/π).
So, the correct answer is (B)

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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