NCERT Exemplar - MCQs

Chapter 6 Class 12 Application of Derivatives
Serial order wise

## (C) (4, 2)                   (D) (1, 1)

This question is similar to Example 17 - Chapter 6 Class 12 - Application of Derivatives

### Transcript

Question 5 The point on the curve y2 = x, where the tangent makes an angle of π/4 with x-axis is (A) (1/2, 1/4) (B) (1/4, 1/2) (C) (4, 2) (D) (1, 1) π¦^2=π₯ Slope of the tangent is ππ/ππ Finding ππ/ππ 2y ππ¦/ππ₯=1 ππ/ππ=π/ππ Since, the tangent makes an angle of π/4 with x-axis i.e., π½=π/π β΄ Slope of tangent =πππ π½ =tanβ‘γπ/4γ =π Equating (1) and (2) π/ππ=π 1=2π¦ 2π¦=1 π=π/π Since, we have to find point on the curve where the tangent makes an angle of π/4 with x-axis Finding π by putting π=π/π in equation of curve π^π=π (π/π)^2=π₯ 1/4 =π₯ π=π/π β΄ Required point = (x, y) = (π/π,π/π). So, the correct answer is (B)