The curve y = x^(1/5) has at (0, 0)
(A) a vertical tangent (parallel to y-axis)
(B) a horizontal tangent (parallel to x-axis)
(C) an oblique tangent
(D) no tangent
Get live Maths 1-on-1 Classs - Class 6 to 12
NCERT Exemplar - MCQs
Question 2
Question 3 Important
Question 4
Question 5
Question 6 Important
Question 7 Important
Question 8 You are here
Question 9 Important
Question 10
Question 11 Important
Question 12 Important
Question 13
Question 14
Question 15
Question 16 Important
Question 17 Important
Question 18 Important
Question 19
Question 20 Important
Question 21 Important
Question 22 Important
Question 23
Question 24 Important
Question 25 Important
Question 26
Question 27
Question 28 Important
Question 29 Important
Question 30 Important
NCERT Exemplar - MCQs
Last updated at March 22, 2023 by Teachoo
Get live Maths 1-on-1 Classs - Class 6 to 12
Question 8 The curve y = π₯^(1/5) has at (0, 0) (A) a vertical tangent (parallel to y-axis) (B) a horizontal tangent (parallel to x-axis) (C) an oblique tangent (D) no tangent Since options are about finding tangent So, finding slope of tangent i.e. π π/π π at (0, 0) Finding π π/π π π¦ = π₯^(1/5) π π/π π = 1/5 π₯^((1/5 β 1) ) = 1/5 π₯^((β4)/5) = π/(ππ^(π/π) ) Finding Slope at (0, 0) Putting π = 0 in ππ¦/ππ₯ π π/π π = 1/(5 (0)^(4/5) ) = 1/0 = β Now, Slope = tan π½ β = tan π tan ΞΈ = β β΄ π½ = 90Β° So tangent makes angle 90Β° with x-axis Thus, tangent is parallel to y-axis i.e. a vertical tangent So, the correct answer is (A)