Ex 9.5, 5 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

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Question 5 Show that. (ii) (9𝑝−5𝑞)^2+180𝑝𝑞=(9𝑝+5𝑞)^2 Solving LHS (9𝑝−5𝑞)^2+180𝑝𝑞 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 Solving RHS (9𝑝+5𝑞)^2 (𝑎+𝑏)^2=𝑎^2+𝑏^2+2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 = (9𝑝)^2+(5𝑞)^2+2(9𝑝)(5𝑞) = 81𝑝^2+25𝑞^2+90𝑝𝑞 Thus LHS = RHS Hence proved

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