Exploring Algebraic Identities - Chapter 4 Class 9 (Ganita Manjari I)

Master Exploring Algebraic Identities - Chapter 4 Class 9 (Ganita Manjari I) with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.

NCERT Solutions

Exploring Algebraic Identities - Chapter 4 Class 9 (Ganita Manjari I) – NCERT Solutions

Each question below opens its complete step-by-step Teachoo solution.

Exercise Set 4.1

2 questions

Ex 4.1, 1

(i)
Using the identity (π‘Ž+𝑏)^2=π‘Ž^2+2π‘Žπ‘+𝑏^2, expand the following (i) (7π‘₯+4𝑦)^2
(7π‘₯+4𝑦)^2

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Ex 4.1, 2

(i)
Using the same identity, find the values of the following: (i) (64)^2
64^2
=(πŸ”πŸŽ+πŸ’)^𝟐

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Exercise Set 4.2

2 questions

Ex 4.2, 1

(i)
Factor completely:
(i) 9π‘₯^2+24π‘₯𝑦+16𝑦^2
Since 32 = 9 and 42 = 16 we can write our expression as

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Ex 4.2, 2

(i)
Find the values of the following using the identity (π‘Žβˆ’π‘)^2=π‘Ž^2βˆ’2π‘Žπ‘+𝑏^2.
(i) (79)^2
79^2
=(πŸ–πŸŽβˆ’πŸ)^𝟐

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Exercise Set 4.3

4 questions

Ex 4.3, 1

(i)
Find the following squares using one of the above identities. Determine which of these identities will make these calculations easier.
(i) 117^2
We can write
117 = 120 – 3
Thus, we use (a – b)2 identity

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Ex 4.3, 2

(i)
Factor using suitable identities:
(i) 16𝑦^2βˆ’24𝑦+9
Here, we can write
16𝑦^2=(πŸ’π’š)^𝟐
9=πŸ‘^𝟐
And, since there βˆ’24𝑦 i.e. negative sign, we use (a – b)2

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Ex 4.3, 3

(i)
Expand the following using the identity
(π‘Ž+𝑏+𝑐)^2=π‘Ž^2+𝑏^2+𝑐^2+2π‘Žπ‘+2𝑏𝑐+2π‘π‘Ž:.
(i) (𝑝+3π‘ž+7π‘Ÿ)^2
(𝒑+πŸ‘π’’+πŸ•π’“)^𝟐

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Ex 4.3, 4

Is this an identity?
(π‘Ž+π‘βˆ’π‘)^2+(π‘Žβˆ’π‘+𝑐)^2+(π‘Žβˆ’π‘βˆ’π‘)^2=2π‘Ž^2+2𝑏^2+2𝑐^2.
We expand the left side individually
Since (π‘Ž+𝑏+𝑐)^2=π‘Ž^2+𝑏^2+𝑐^2+2π‘Žπ‘+2𝑏𝑐+2π‘Žπ‘

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Exercise Set 4.4

3 questions

Ex 4.4, 1

(i)
Fill in the blanks to complete the following identities:
(i) 𝑠^2βˆ’11𝑠+24=( ____ ) ( ____ )
We need to factorise 𝒔^πŸβˆ’πŸπŸπ’”+πŸπŸ’

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Ex 4.4, 2

(i)
Select and use the identity that will help you to find the following products without multiplying directly:
(i) (41)^2
We can write
41 = 40 + 1
Thus, we use (a + b)2 identity

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Ex 4.4, 3

(i)
Factor the following:
(i) 9π‘Ž^2+𝑏^2+4𝑐^2βˆ’6π‘Žπ‘+12π‘Žπ‘βˆ’4𝑏𝑐
Here,
There are 3 square terms, so we use (a + b + c)2
Our square terms would be πŸ—π’‚^𝟐, 𝒃^𝟐 , πŸ’π’„^𝟐
But, we have negative terms like βˆ’πŸ”π’‚π’ƒ and βˆ’πŸ’π’ƒπ’„
Since both negative term has 𝒃, it is a negative term
So, we write 𝒃^𝟐=(βˆ’π’ƒ)^𝟐

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Exercise Set 4.5

6 questions

Ex 4.5, 1 (i)

Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:
(i) (3𝑝^2 βˆ’ 3π‘π‘ž βˆ’ 18π‘ž^2)/(𝑝^2 + 3π‘π‘ž βˆ’ 10π‘ž^2 )
Here,
In both numerator and denominator, there are negative square terms
We cannot use (πšβˆ’π›)^𝟐 or (𝐚+𝒃)^𝟐 because in both these formulas, the square terms are positive
Thus, we factorise both numerator and denominator using using splitting the middle term
We take p as main variable, and q as constant

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Ex 4.5, 1 (ii)

Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:
(ii) (𝑛^3 βˆ’ 3𝑛^2 π‘š + 3π‘›π‘š^2 βˆ’ π‘š^3)/(5π‘š^2 βˆ’ 10π‘šπ‘› + 5𝑛^2 )
Factorising numerator and denominator separately

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Ex 4.5, 1 (iii)

Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:
(iii) (𝑀^3 βˆ’ 𝑣^3 + π‘₯^3 + 3𝑀𝑣π‘₯)/(𝑀^2 + 𝑣^2 + π‘₯^2 βˆ’ 2𝑀𝑣 βˆ’ 2𝑣π‘₯ + 2𝑀π‘₯)
Since there is Sum of 3 cubes here, we use the formula
x3 + y3 + z3 βˆ’ 3xyz = (x + y + z) (x2 + y2 + z2 βˆ’ xy βˆ’ yz βˆ’ zx)

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Ex 4.5, 1 (iv)

Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:
(iv) (4𝑦^2 βˆ’ 20𝑦𝑧 + 25𝑧^2)/((25𝑧^2 βˆ’ 4𝑦^2 ) )
Factorising numerator and denominator separately

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Ex 4.5, 1 (v)

Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:
(v) (π‘₯^2 + π‘₯ βˆ’ 6)(π‘₯^2 βˆ’ 7π‘₯ + 12)/(π‘₯^2 βˆ’ 6π‘₯ + 8)(π‘₯^2 βˆ’ 9)
We have 4 terms here, and we will factorise them separately

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Ex 4.5, 1 (vi)

Simplify the following rational expressions assuming that the expressions in the denominators are not equal to zero:
(vi) (𝑝^4βˆ’16)/(𝑝^2 βˆ’ 4𝑝 + 4)
Factorising numerator and denominator separately

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End-of-Chapter Exercises

13 questions

Question 1

(i)
Use suitable identities to find the following products: (i) (βˆ’3π‘₯+4)^2
Now,
(βˆ’3π‘₯+4)^2=(πŸ’βˆ’πŸ‘π’™)^𝟐

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Question 2

(i)
Find the values using suitable identities: (i) 17 Γ— 21
Writing
17 Γ— 21 = (19 – 2) Γ— (19 + 2)

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Question 3

(i)
Factor the following algebraic expressions: (i) 4𝑦^2+1+1/(16𝑦^2 )
Here, we can write
4𝑦^2=(πŸπ’š)^𝟐
1/(16𝑦^2 )=(𝟏/πŸ’π’š)^𝟐
And, since there +1 i.e. positive sign, we use (a + b)2

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Question 4

(i)
Simplify the following: (i) (4π‘₯^2 + 4π‘₯ + 1)/(4π‘₯^2 βˆ’ 1)
Factorising numerator and denominator separately

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Question 5

(i)
Find possible expressions for the length and breadth of each of the following rectangles whose areas are given by the following expressions in square units. (i) 25π‘Ž^2βˆ’30π‘Žπ‘+9𝑏^2
Because Area = Length Γ— Breadth
We factor the expression into 2 brackets to give us Length and Breadth

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Question 6

(i)
Find possible expressions for the length, breadth, and heights of each of the following cuboids whose volumes are given by the following expressions in cubic units. (i) 6π‘Ž^2βˆ’24𝑏^2
Because Volume = Length Γ— Breadth Γ— Height
We factor the expression into 3 brackets to give us Length, Breadth and Height

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Question 7

The village playground is shaped as a square of side 40 metres. A path of width s metres is created around the playground for people to walk. Find an expression for the area of the path in terms of s.
Let’s draw a diagram
Now, we have
Bigger square of side 40 + s + s = 40 + 2s
Playground square of side 40

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Question 8

If a number plus its reciprocal equals 10/3, find the number.
Let Number = 𝒙
Thus,
Reciprocal of our number = 𝟏/𝒙

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Question 9

A rectangular pool has area 2π‘₯^2+7π‘₯+3 square hastas. If its width is 2π‘₯+1 hastas, find its length. Hasta was a unit used to measure length.
We know that
Area of rectangle = Length Γ— Breadth
πŸπ’™^𝟐+πŸ•π’™+πŸ‘ = Length Γ— (πŸπ’™+𝟏)

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Question 10

If both π‘₯βˆ’2 and π‘₯βˆ’1/2 are factors of 𝑝π‘₯^2+5π‘₯+π‘Ÿ, show that
𝑝=π‘Ÿ.
If both π‘₯βˆ’2 and π‘₯βˆ’1/2 are factors of 𝑝π‘₯^2+5π‘₯+π‘Ÿ,
Then we can write
π’Œ(π’™βˆ’πŸ)(π’™βˆ’πŸ/𝟐)= 𝒑𝒙^𝟐+πŸ“π’™+𝒓
Where k is any constant

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Question 11

If π‘Ž+𝑏+𝑐=5 and π‘Žπ‘+𝑏𝑐+π‘π‘Ž=10, then prove that π‘Ž^3+𝑏^3+𝑐^3βˆ’3π‘Žπ‘π‘=βˆ’25.
Since there are 3 cubes, we use 𝒂^πŸ‘+𝒃^πŸ‘+𝒄^πŸ‘formula

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Question 12

By factoring the expression, check that 𝑛^3βˆ’π‘› is always divisible by 6 for all natural numbers 𝑛. Give reasons.
First, we factorise 𝑛^3βˆ’π‘›

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Question 13

(i)
Find the value of
(i) π‘₯^3+𝑦^3βˆ’12π‘₯𝑦+64, when π‘₯+𝑦=βˆ’4

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Why Learn This With Teachoo?

Exploring Algebraic Identities is Chapter 4 of NCERT Class 9 Ganita Manjari Part 1. It develops identities through patterns and area models and applies them to expansion, factorisation, rational expressions and word problems. Students study consecutive square numbers, visualise familiar identities, factor by algebra tiles and splitting the middle term, and generate new identities. Teachoo provides structured explanations and solutions for Exercise Sets 4.1 to 4.5 and the end-of-chapter exercises.

What is an algebraic identity?

An identity is an equality true for every permitted value of its variables. This differs from an equation that may be true only for particular solutions. Familiar identities include:

  • (a + b)² = a² + 2ab + b²;

  • (a − b)² = a² − 2ab + b²; and

  • a² − b² = (a − b)(a + b).

Area diagrams and algebra tiles make each term visible. A large square with side a + b contains regions of areas a², ab, ab and b², explaining the middle term 2ab. Visualisation turns identities from memorised formulas into relationships that can be reconstructed.

Consecutive squares and additional identities

Differences between consecutive square numbers follow an odd-number pattern. Algebra shows (n + 1)² − n² = 2n + 1. Students use such patterns to conjecture and prove identities.

More identities extend multiplication of binomials and special expressions. Rewriting a² − b² in different forms helps recognise hidden factorisation opportunities. The important skill is matching an expression’s structure with a valid identity rather than forcing every expression into the same template.

Factorisation methods

Factorisation reverses expansion. Common factors should be extracted first. Algebra tiles provide a geometric representation of arranging terms into a rectangle. Splitting the middle term factors a quadratic expression ax² + bx + c by finding two terms whose sum is b and whose product is ac, followed by grouping.

Students also find new identities by expansion or rearrangement and simplify rational expressions. Cancellation is valid only for common factors multiplying the entire numerator and denominator, with excluded values noted when a denominator can be zero.

Word problems use identities to represent areas, products, consecutive numbers and numerical shortcuts.

Topics covered on Teachoo

Teachoo covers:

  • consecutive square-number patterns;

  • visualising algebraic identities;

  • Exercise Set 4.1;

  • factorisation using identities;

  • Exercise Set 4.2;

  • additional identities;

  • Exercise Set 4.3;

  • rewriting the difference-of-squares identity;

  • factorisation with algebra tiles;

  • splitting the middle term;

  • Exercise Set 4.4;

  • discovering new identities;

  • simplifying rational expressions;

  • Exercise Set 4.5;

  • word problems; and

  • end-of-chapter exercise solutions.

Learning outcomes

Students should be able to distinguish an identity from an equation, derive and apply identities, expand expressions and factor them by common factor, identity or middle-term splitting. They should model products with algebra tiles, simplify rational expressions under valid conditions and prove a number pattern algebraically. They should also verify a factorisation by multiplying the factors back.

Why is this chapter important?

Identities provide efficient tools for algebraic manipulation, mental calculation and proof. Factorisation supports equation solving, rational expressions, coordinate geometry and later quadratic mathematics. The chapter develops reversible thinking: every expansion can be checked by factorisation, and every factorisation by expansion.

How Teachoo helps

Teachoo separates each identity and factorisation method. Before choosing a method, arrange terms in standard order and remove any common factor. Look for perfect squares, a difference of squares or a suitable middle-term split. After factorising, expand the result to verify it exactly.

For rational expressions, factor numerator and denominator fully before cancelling. State restrictions from the original denominator. Compare your attempt with Teachoo’s solution and locate the first structural decision that differs.

Common mistakes to avoid

Do not write (a + b)² as a² + b². Cancellation cannot cross addition or subtraction; only common factors may cancel. When splitting the middle term, the two chosen terms must satisfy both the required sum and product. An identity remains subject to domain restrictions when it is used inside a rational expression.

Quick revision checklist

Derive the square identities with an area model, expand several products and factor the results back. Practise recognising a difference of squares even when common factors or rearrangement hide it. Factor one quadratic by splitting the middle term and verify the answer by multiplication. Simplify a rational expression only after complete factorisation and list excluded variable values. Finally, prove one numerical pattern with algebra instead of relying on examples alone.

Deeper reasoning and concept connections

Study Exploring Algebraic Identities (Ganita Manjari Part 1) through comparison and justification. Place two related examples side by side, identify the decisive difference and explain why one method works in each case. Then create a new example and a deliberate non-example. This forces the definition to do real work and exposes gaps that passive reading hides.

Students should also practise reversing questions. After solving for an answer, ask what question could have produced it, whether more than one answer is possible and which extra condition would make the result unique. Reverse reasoning develops flexibility and is especially useful for missing-value, assertion–reason and error-analysis questions. The goal is to understand the network of ideas, not merely the order of a textbook solution.

How to solve unfamiliar and competency-based questions

Begin by separating facts from conclusions. Facts are given by the question or a known property; conclusions must be derived. Draw or rewrite the problem so each fact has a visible place. If several methods are possible, prefer the one with fewer assumptions and an easy final check. Record intermediate results rather than doing everything mentally.

Competency questions often change context without changing mathematics. Replace names and story details with variables, shapes, sets or data values. After solving, restore the context and check feasibility: counts should be whole where required, lengths and areas should have suitable units, probabilities should lie between 0 and 1, and constructed figures should satisfy every stated condition.

What complete mastery looks like

For Exploring Algebraic Identities (Ganita Manjari Part 1), a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.

Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.

Additional frequently asked questions

What should a student know before starting Exploring Algebraic Identities (Ganita Manjari Part 1)?

Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.

How can a student check an answer in Exploring Algebraic Identities (Ganita Manjari Part 1)?

Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.

How many questions are enough for strong preparation?

There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.

How should Teachoo solutions be used without becoming dependent on them?

Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.

Frequently asked questions

What is the difference between an identity and an equation?

An identity is true for all permitted variable values; an equation may be true only for specific values.

How can factorisation be checked?

Multiply the factors. The expanded result should reproduce the original expression exactly.

When may terms be cancelled in a rational expression?

Only when they are common non-zero factors of the entire numerator and denominator, not terms joined by addition.

Recognise the expression’s structure first. The correct identity or factorisation method then becomes much easier to select.