A rectangular pool has area 2x^2 + 7x + 3 square hastas. If its width - End-of-Chapter Exercises

part 2 - Question 9 - End-of-Chapter Exercises - Chapter 4 Class 9 - Exploring Algebraic Identities (Ganita Manjari I) - Maths Class 9

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Question 9 A rectangular pool has area 2๐‘ฅ^2+7๐‘ฅ+3 square hastas. If its width is 2๐‘ฅ+1 hastas, find its length. Hasta was a unit used to measure length. We know that Area of rectangle = Length ร— Breadth ๐Ÿ๐’™^๐Ÿ+๐Ÿ•๐’™+๐Ÿ‘ = Length ร— (๐Ÿ๐’™+๐Ÿ) Thus, we need to factorise ๐Ÿ๐’™^๐Ÿ+๐Ÿ•๐’™+๐Ÿ‘ Now, ๐Ÿ๐’™^๐Ÿ+๐Ÿ•๐’™+๐Ÿ‘ Factorising by Splitting the middle term = 2๐‘ฅ^2+๐Ÿ”๐’™+๐’™+3 = 2๐‘ฅ(๐‘ฅ+3)+1(๐‘ฅ+3) = (๐Ÿ๐’™+๐Ÿ)(๐’™+๐Ÿ‘) Since Width = (๐Ÿ๐’™+๐Ÿ) Thus, Length = (๐ฑ+๐Ÿ‘) hastas Splitting the middle term method We need to find two numbers whose Sum = 7 Product = 2 ร— 3 = 6 Since sum is negative but product is positive. Thus, both numbers are positive

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