Ex 7.6, 5 - Chapter 7 Class 12 Integrals
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 7.6, 5 ๐ฅ logโก2๐ฅ Integrating the function ๐ค.๐.๐ก.๐ฅ โซ1โใ๐ฅ logโก2๐ฅ ใ ๐๐ฅ Hence, we take First function :- ๐(๐ฅ)=logโก(2๐ฅ) Second function :- g(๐ฅ)=๐ฅ โซ1โใ๐ฅ logโก๐ฅ ใ ๐๐ฅ=โซ1โ(logโก๐ฅ )๐ฅ ๐๐ฅ =logโก(2๐ฅ) โซ1โ๐ฅ ๐๐ฅโโซ1โ(๐(logโก2๐ฅ )/๐๐ฅ โซ1โใ๐ฅ.๐๐ฅใ)๐๐ฅ =logโก(2๐ฅ) (๐ฅ^2/2)โโซ1โใ1/2๐ฅ . 2 .๐ฅ^2/2. ๐๐ฅใ =ใ๐ฅ^2/2 logใโก(2๐ฅ)โโซ1โใ๐ฅ/2. ๐๐ฅใ =ใ๐ฅ^2/2 logใโก(2๐ฅ)โ1/2 โซ1โใ๐ฅ ๐๐ฅใ =ใ๐ฅ^2/2 logใโก(๐ฅ)โ 1/2 (๐ฅ^2/2)+๐ถ =ใ๐ฅ^2/2 logใโก(2๐ฅ)โ ๐ฅ^2/4 +๐ถ
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo