Ex 10.3

Ex 10.3, 1

Ex 10.3, 2

Ex 10.3, 3 Important

Ex 10.3, 4

Ex 10.3, 5 Important

Ex 10.3, 6

Ex 10.3, 7

Ex 10.3, 8 You are here

Ex 10.3, 9 Important

Ex 10.3, 10 Important

Ex 10.3, 11

Ex 10.3, 12 Important

Ex 10.3, 13 Important

Ex 10.3, 14

Ex 10.3, 15 Important

Ex 10.3, 16 Important

Ex 10.3, 17

Ex 10.3, 18 (MCQ) Important

Last updated at April 21, 2021 by Teachoo

Ex 10.3, 8 Find the magnitude of two vectors 𝑎 ⃗ and 𝑏 ⃗, having the same magnitude and such that the angle between them is 60° and their scalar product is 1/2 . Given, magnitude of two vectors 𝑎 ⃗ and 𝑏 ⃗ is same So, |𝑎 ⃗ | = |𝑏 ⃗ | We know that , 𝑎 ⃗ . 𝑏 ⃗ = |𝑎 ⃗ | |𝑏 ⃗ | cos θ , θ is the angle between 𝑎 ⃗ and 𝑏 ⃗ Given θ = 60° & 𝑎 ⃗ . 𝑏 ⃗ = 1/2 Now, 𝑎 ⃗ . 𝑏 ⃗ = |𝑎 ⃗ | |𝑏 ⃗ | cos θ 𝑎 ⃗ . 𝑏 ⃗ = |𝑎 ⃗ | |𝑎 ⃗ | cos 60° 1/2 = |𝑎 ⃗ |2 × 1/2 |𝑎 ⃗ |2 = 1 |𝑎 ⃗ | = ± 1 Since, magnitude of a vector is not negative, So, |𝑎 ⃗ | = 1 So |𝒂 ⃗ | = |𝒃 ⃗ | = 1 Thus, magnitude of 𝑎 ⃗ and 𝑏 ⃗ is 1.