
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 10.3
Ex 10.3, 2
Ex 10.3, 3 Important
Ex 10.3, 4
Ex 10.3, 5 Important
Ex 10.3, 6
Ex 10.3, 7
Ex 10.3, 8 You are here
Ex 10.3, 9 Important
Ex 10.3, 10 Important
Ex 10.3, 11
Ex 10.3, 12 Important
Ex 10.3, 13 Important
Ex 10.3, 14
Ex 10.3, 15 Important
Ex 10.3, 16 Important
Ex 10.3, 17
Ex 10.3, 18 (MCQ) Important
Last updated at May 29, 2023 by Teachoo
Ex 10.3, 8 Find the magnitude of two vectors 𝑎 ⃗ and 𝑏 ⃗, having the same magnitude and such that the angle between them is 60° and their scalar product is 1/2 . Given, magnitude of two vectors 𝑎 ⃗ and 𝑏 ⃗ is same So, |𝑎 ⃗ | = |𝑏 ⃗ | We know that , 𝑎 ⃗ . 𝑏 ⃗ = |𝑎 ⃗ | |𝑏 ⃗ | cos θ , θ is the angle between 𝑎 ⃗ and 𝑏 ⃗ Given θ = 60° & 𝑎 ⃗ . 𝑏 ⃗ = 1/2 Now, 𝑎 ⃗ . 𝑏 ⃗ = |𝑎 ⃗ | |𝑏 ⃗ | cos θ 𝑎 ⃗ . 𝑏 ⃗ = |𝑎 ⃗ | |𝑎 ⃗ | cos 60° 1/2 = |𝑎 ⃗ |2 × 1/2 |𝑎 ⃗ |2 = 1 |𝑎 ⃗ | = ± 1 Since, magnitude of a vector is not negative, So, |𝑎 ⃗ | = 1 So |𝒂 ⃗ | = |𝒃 ⃗ | = 1 Thus, magnitude of 𝑎 ⃗ and 𝑏 ⃗ is 1.