Theorems (and their Proofs)
Last updated at May 26, 2026 by Teachoo
Transcript
Theorem Angles in the same segment of a circle are equal. Given: A circle with center at O. Points P & Q on this circle subtends angles ∠ PAQ and ∠ PBQ at points A and B respectively. To Prove: ∠PAQ = ∠PBQ Proof: Chord PQ subtends ∠ POQ at the center From Theorem 9: Angle subtended by an arc at the centre is double the angle subtended by it at any other point on circle ∴ ∠ POQ = 2∠PAQ ∠POQ = 2∠PBQ From (1) and (2) 2∠PBQ = 2∠PAQ ∠ PBQ = ∠PAQ Hence proved