Last updated at Feb. 3, 2020 by Teachoo

Transcript

Misc 6 Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines x – 7y + 5 = 0 and 3x + y = 0. First we calculate point of intersection of lines x – 7y + 5 = 0 & 3x + y = 0 Solving (1) x – 7y + 5 = 0 x = 7y − 5 Putting value of x in (2) 3x + y = 0 3(7y − 5) + y = 0 21y − 15 + y = 0 21y + y − 15 = 0 22y − 15 = 0 22y = 15 y = 15/22 Putting value of y = 15/22 in (1) x – 7y + 5 = 0 x – 7(15/22) + 5 = 0 x = 7(15/22) − 5 x = (15 × 7 − 22 × 5)/22 x = (105 − 110)/22 x = ( −5)/22 Hence point of intersection is (( −5)/22, 15/22) The equation of line parallel to y-axis is of the form x = p where p is some constant Given that this equation of line passing through point of intersection (( − 5)/22, 15/22) Hence point (( − 5)/22, 15/22) will satisfy the equation of line Putting x = ( − 5)/22 in the equation x = p ( −5)/22 = p p = ( −5)/22 Thus, Required equation of line is x = p Putting values x = ( −𝟓)/𝟐𝟐

Miscellaneous

Misc 1
Important

Misc 2 Important

Misc 3 Important

Misc 4

Misc 5

Misc 6 Important You are here

Misc 7

Misc 8 Important

Misc 9 Important

Misc 10

Misc 11 Important

Misc 12 Important

Misc 13

Misc 14

Misc 15 Important

Misc 16 Important

Misc 17

Misc 18 Important

Misc 19 Important

Misc 20 Important

Misc 21 Important

Misc 22 Important

Misc 23

Misc 24 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.