Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Miscellaneous

Misc 1
Important
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Misc 2 Important

Misc 3

Misc 4

Misc 5 Important

Misc 6

Misc 7 Important

Misc 8 Important

Misc 9

Misc 10 Important

Misc 11 Important

Misc 12

Misc 13

Misc 14 Important

Misc 15 Important

Misc 16

Misc 17 Important

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Misc 23 Important

Question 1 Important Deleted for CBSE Board 2024 Exams

Last updated at May 29, 2023 by Teachoo

Misc 1 Find the values of k for which the line (k – 3) x – (4 – k2)y + k2 – 7k + 6 = 0 is Parallel to the x-axis, Any line parallel to x-axis is of the form y = p where p is constant So, there is no x term Since Line (k – 3) x – (4 – k2) y + k2 – 7k + 6 = 0 is parallel to x-axis Hence, (k − 3)x = 0 k – 3 = 0/𝑥 k – 3 = 0 k = 3 Misc 1 Find the values of k for which the line (k – 3) x – (4 – k2) y + k2 – 7k + 6 = 0 is (b) Parallel to the y-axis, Any line parallel to y-axis is of the form x = p where p is constant So, there is no y term Since line (k – 3) x – (4 – k2) y + k2 – 7k + 6 = 0 is parallel to y-axis Hence, –(4 – k2) y = 0 −(4 − k2) = 0/𝑦 –4 + k2 = 0 k2 = 4 k = ± √4 k = ± 2 Hence k = 2 or −2 Misc 1 Find the values of k for which the line (k – 3) x – (4 – k2) y + k2 – 7k + 6 = 0 is (c) Passing through origin If the line passing through the origin i.e. (0, 0) will satisfy the equation of line Putting x = 0 & y = 0 in equation (k − 3)x − (4 − k2)y + k2 − 7k + 6 = 0 (k − 3)0 − (4 − k2)0 + k2 − 7k + 6 = 0 k2 − 7k + 6 = 0 k2 − 6k − k + 6 = 0 k(k − 6) − 1(k − 6) = 0 k(k − 6) − 1(k − 6) = 0 (k − 1)(k − 6) = 0 So, k = 1 or k = 6