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  1. Chapter 10 Class 11 Straight Lines
  2. Serial order wise

Transcript

Example 1 Find the slope of the lines: Passing through the points (3, โ€“2) and (โ€“1, 4) We know that slope between two points (x1, y1) & (x2, y2) is m = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) Here x1 = 3, y1 = โˆ’2, & x2 = โˆ’1, y2 = 4 Putting values Slope = (4 โˆ’ (โˆ’2))/(โˆ’1 โˆ’ 3) = (4 + 2)/( โˆ’4) = 6/( โˆ’4) = ( โˆ’๐Ÿ‘)/๐Ÿ Example 1 Find the slope of the lines: (b) Passing through the points (3, โ€“2) and (7, โ€“2), We know that slope between two points (x1,y1) & (x2,y2) is m = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) Here x1 = 3, y1 = โˆ’2, & x2 = 7, y2 = โˆ’2 Putting values Slope = ( โˆ’2 โˆ’ ( โˆ’2))/(7 โˆ’ 3) = ( โˆ’2 + 2)/4 = 0/4 = 0 Example 1 Find the slope of the lines: (c) Passing through the points (3, โ€“ 2) and (3, 4), We know that slope between two points (x1, y1) & (x2, y2) is m = (๐‘ฆ_2 โˆ’ ๐‘ฆ_1)/(๐‘ฅ_2 โˆ’ ๐‘ฅ_1 ) Here x1 = 3, y1 = โˆ’2, & x2 = 3, y2 = 4 Putting values Slope = (4 โˆ’ (โˆ’2))/(3 โˆ’ 3) = (4 + 2)/0 = ๐Ÿ”/๐ŸŽ = โˆž (not defined) Example 1 Find the slope of the lines: (d) Making inclination of 60ยฐ with the positive direction of x-axis. Slope = m = tan ฮธ Given ๐œƒ = 60ยฐ Hence, m = tan ฮธ = tan 60ยฐ = โˆš๐Ÿ‘

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.