Example 5 - Chapter 10 Class 11 Straight Lines (Term 1)
Last updated at May 29, 2018 by Teachoo
Examples
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Example 1 (b)
Example 1 (c) Important
Example 1 (d)
Example 2 Important
Example 3 Important
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Example 5 You are here
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Example 9 (i)
Example 9 (ii) Important
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Example 11 Deleted for CBSE Board 2023 Exams
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Example 13 Important
Example 14 Important Deleted for CBSE Board 2023 Exams
Example 15 Important
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Example 25 Important
Transcript
Example 5 In Fig 10.9, time and distance graph of a linear motion is given. Two positions of time and distance are recorded as, when T = 0, D = 2 and when T = 3, D = 8. Using the concept of slope, find law of motion, i.e., how distance depends upon time. Let A = (0, 2) , B = (3, 8) , C = (T, D) Points A,B, C lie on the line So, A, B & C are collinear Slope of AB = Slope of BC We know that slope of a line through the points (x1, y1)(x2, y2)is m = ( 2 1)/( 2 1) D 8 = 2T 6 D = 2T 6 + 8 D = 2T + 2 D = 2(T + 1) Here, we can see that as T increases , D increases Hence, Distance depends on time.
