Example 5 - Class 11
Last updated at May 29, 2018 by Teachoo
Transcript
Example 5 In Fig 10.9, time and distance graph of a linear motion is given. Two positions of time and distance are recorded as, when T = 0, D = 2 and when T = 3, D = 8. Using the concept of slope, find law of motion, i.e., how distance depends upon time. Let A = (0, 2) , B = (3, 8) , C = (T, D) Points A,B, C lie on the line So, A, B & C are collinear ∴ Slope of AB = Slope of BC We know that slope of a line through the points (x1, y1)(x2, y2)is m = (𝑦2 − 𝑦1)/(𝑥2 − 𝑥1) D – 8 = 2T – 6 D = 2T – 6 + 8 D = 2T + 2 D = 2(T + 1) Here, we can see that as T increases , D increases Hence, Distance depends on time.
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.
