Example 19 - Chapter 10 Class 11 Straight Lines
Last updated at May 29, 2018 by Teachoo
Transcript
Example 19 Find the distance between the parallel lines 3x 4y + 7 = 0 and 3x 4y + 5 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Distance between the parallel lines 3x 4y + 7 = 0 & 3x 4y + 5 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Putting values d = |7 5|/ ((3)^2 + ( 4)^2 ) d = |2|/ (9 + 16) d = 2/ 25 d = 2/ (5 5) d = 2/5 Thus, the required distance is 2/5 units
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.