Example 10 Find the distance between the parallel lines 3x 4y + 7 = 0 and 3x 4y + 5 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Distance between the parallel lines 3x 4y + 7 = 0 & 3x 4y + 5 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Putting values d = |7 5|/ ((3)^2 + ( 4)^2 ) d = |2|/ (9 + 16) d = 2/ 25 d = 2/ (5 5) d = 2/5 Thus, the required distance is 2/5 units

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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