# Example 19 - Chapter 10 Class 11 Straight Lines

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 19 Find the distance between the parallel lines 3x 4y + 7 = 0 and 3x 4y + 5 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Distance between the parallel lines 3x 4y + 7 = 0 & 3x 4y + 5 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Putting values d = |7 5|/ ((3)^2 + ( 4)^2 ) d = |2|/ (9 + 16) d = 2/ 25 d = 2/ (5 5) d = 2/5 Thus, the required distance is 2/5 units

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.