# Example 11 - Chapter 10 Class 11 Straight Lines

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 11 Find the equation of the line whose perpendicular distance from the origin is 4 units and the angle which the normal makes with positive direction of x-axis is 15 . We need to find equation of line Perpendicular distance of AB from origin is 4 units & angle which the normal makes with (+)ve direction of x-axis is 15 By Normal from Equation of line is x cos + y sin = p where, p = normal distance from the origin & = angle which makes by the normal with positive x-axis Here p = 4 & = 15 Putting values x cos + y sin = p x cos 15 + y sin 15 = 4 x (( 3 + 1)/(2 2)) + y (( 3 1)/(2 2)) = 4 ( ( 3 + 1) + ( 3 1))/(2 2) = 4 x( 3 + 1) + y( 3 1) = 4 2 2 ( 3 + 1)x + ( 3 1)y = 8 2 Which Is the required equation

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.