Example 13 - Chapter 10 Class 11 Straight Lines

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Example 13 Equation of a line is 3x 4y + 10 = 0. Find its (i) slope 3x 4y + 10 = 0 4y = 3x 10 4y = (3x + 10) 4y = 3x + 10 y = (3 + 10)/4 y = 3/4 x + 10/4 y = 3/4x + 5/2 The above equation is of the form y = mx + c where m is the slope & c is the y-intercept Here, m = 3/4 & c = 5/2 Hence, slope m = 3/4 & y-intercept = 5/2 Example 13 Equation of a line is 3x 4y + 10 = 0. Find its (ii) x and y-intercepts. 3x 4y + 10 = 0 3x 4y = 10 Dividing both sides by 10 (3 4 )/( 10) = ( 10)/( 10) 3 /( 10) 4 /( 10) = 1 3 /( 10) + 4 /( 10) = 1 /(( 10)/3) + /(10/4) = 1 /(( 10)/3) + /(5/2) = 1 The above equation of the form / + /( ) = 1 Hence, a = x-intercept = ( 10)/3 & b = y-intercept = 5/2