Example 5 - Chapter 9 Class 11 Straight Lines

Last updated at August 5, 2026 by

Example 5 - Find equation of line through (-2, 3), slope -4 - Examples

part 2 - Example 5 - Examples - Serial order wise - Chapter 9 Class 11 Straight Lines

 

Take a fresh quiz. Then take another.
Every attempt is a new AI-adaptive Teachoo quiz with 7 questions, selected from your answers, mistakes, and progress.
Remove Ads

Transcript

Example 5 Find the equation of the line through (– 2, 3) with slope – 4. We know that equation of line passing through point (x0 y0) with slope m is y – y0 = m(x – x0) Here Slope = m = -4 Point (x0, y0) = (-2, 3) Hence x0 = -2 , y0 = 3 Putting the values (y – 3) = –4(x – (-2)) (y – 3) = –4(x + 2) y – 3 = – 4x – 8 y + 4x – 3 + 8 = 0 y + 4x + 5 = 0 Hence, the required equation is y + 4x + 5 = 0

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.