Example 7 - Chapter 10 Class 11 Straight Lines (Term 1)
Last updated at May 29, 2018 by Teachoo
Transcript
Example 7 Find the equation of the line through (– 2, 3) with slope – 4. We know that equation of line passing through point (x0 y0) with slope m is y – y0 = m(x – x0) Here Slope = m = -4 Point (x0, y0) = (-2, 3) Hence x0 = -2 , y0 = 3 Putting the values (y – 3) = –4(x – (-2)) (y – 3) = –4(x + 2) y – 3 = – 4x – 8 y + 4x – 3 + 8 = 0 y + 4x + 5 = 0 Hence, the required equation is y + 4x + 5 = 0
Examples
Example 1 (a)
Example 1 (b)
Example 1 (c) Important
Example 1 (d)
Example 2 Important
Example 3 Important
Example 4
Example 5
Example 6 Important
Example 7 You are here
Example 8
Example 9 (i)
Example 9 (ii) Important
Example 10
Example 11
Example 12
Example 13 Important
Example 14 Important
Example 15 Important
Example 16
Example 17
Example 18 Important
Example 19
Example 20
Example 21 Important
Example 22 Important
Example 23
Example 24 Important
Example 25 Important
Chapter 10 Class 11 Straight Lines (Term 1)
Serial order wise
- Ex 10.1
- Ex 10.2
- Ex 10.3
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Examples
- Miscellaneous
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.