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Example 5 Find the equation of the line through (– 2, 3) with slope – 4. We know that equation of line passing through point (x0 y0) with slope m is y – y0 = m(x – x0) Here Slope = m = -4 Point (x0, y0) = (-2, 3) Hence x0 = -2 , y0 = 3 Putting the values (y – 3) = –4(x – (-2)) (y – 3) = –4(x + 2) y – 3 = – 4x – 8 y + 4x – 3 + 8 = 0 y + 4x + 5 = 0 Hence, the required equation is y + 4x + 5 = 0

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.