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Example 7 - Chapter 10 Class 11 Straight Lines (Term 1)
Last updated at May 29, 2018 by Teachoo
Examples
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Example 1 (b)
Example 1 (c) Important
Example 1 (d)
Example 2 Important
Example 3 Important
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Example 6 Important
Example 7 You are here
Example 8
Example 9 (i)
Example 9 (ii) Important
Example 10
Example 11 Deleted for CBSE Board 2023 Exams
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Example 13 Important
Example 14 Important Deleted for CBSE Board 2023 Exams
Example 15 Important
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Example 18 Important
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Example 21 Important
Example 22 Important
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Transcript
Example 7 Find the equation of the line through (– 2, 3) with slope – 4. We know that equation of line passing through point (x0 y0) with slope m is y – y0 = m(x – x0) Here Slope = m = -4 Point (x0, y0) = (-2, 3) Hence x0 = -2 , y0 = 3 Putting the values (y – 3) = –4(x – (-2)) (y – 3) = –4(x + 2) y – 3 = – 4x – 8 y + 4x – 3 + 8 = 0 y + 4x + 5 = 0 Hence, the required equation is y + 4x + 5 = 0
