Example 6 - Equation of line through (1, -1) and (3, 5) - Examples - Examples

part 2 - Example 6 - Examples - Serial order wise - Chapter 9 Class 11 Straight Lines

Share on WhatsApp

Transcript

Example 6 Write the equation of the line through the points (1, 1) and (3, 5). We know that equation of line through two points (x1, y1) & (x2, y2) is y y1 = (y2 y1)/(x2 x1) (x x1) Since equation of the line through the points (1, 1) and (3, 5). Here, x1 = 1, y1 = 1, & x2 = 3 and y2 = 5 Putting values (y (-1)) = (5 ( 1))/(3 1) (x 1) y + 1 = (5 + 1)/2 (x 1) y + 1 = 6/2 (x 1) y + 1 = 3(x 1) y + 1 = 3x 3 y 3x + 1 3 = 0 y 3x 2 = 0 Hence the required equation is y 3x 2 = 0

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo