This question is similar to Chapter 8 Class 12 Application of Integrals - Ex 8.1

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https://www.teachoo.com/3327/730/Ex-8.1--3---Find-area-x2--4y--y--2--y--4-and-y-axis---NCERT/category/Ex-8.1/

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[SPQ 12] Find out the area of shaded region in the enclosed figure - CBSE Class 12 Sample Paper for 2026 Boards

part 2 - Question 23 (B) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 23 (B) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12 part 4 - Question 23 (B) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Transcript

Question 23 (B) Find out the area of shaded region in the enclosed figure. Let’s redraw the figure The curve is 𝒙^𝟐=π’š We have to find area between y = 0 and y = 4 ∴ We have to find area of BNO Area of BNO = ∫_𝟎^πŸ’β–’π’™ π’…π’š We know that π‘₯^2=𝑦 Taking square root on both sides 𝒙="Β±" βˆšπ’š Since, BNO is in 1st Quadrant We take positive value of x ∴ 𝒙=βˆšπ’š Area of BCFE = ∫_0^4β–’π‘₯ 𝑑𝑦 = ∫_𝟎^πŸ’β–’βˆšπ’š π’…π’š = ∫_0^4β–’γ€–(𝑦)^(1/2) 𝑑𝑦〗 = [𝑦^(3/2)/(3/2)]_0^4 = 2/3 [𝑦^(3/2) ]_2^4 = 𝟐/πŸ‘ [(πŸ’)^(πŸ‘/𝟐 )βˆ’(𝟎)^(πŸ‘/𝟐) ] = 2/3 [(4)^(3/2 ) ] = 𝟐/πŸ‘ [𝟐^(𝟐 Γ—πŸ‘/𝟐) ] = 2/3 Γ— 2^3 = (2 Γ— 8)/3 = πŸπŸ”/πŸ‘ Thus, Area = πŸπŸ”/πŸ‘ square units Area of BCFE = ∫_0^4β–’π‘₯ 𝑑𝑦 = ∫_𝟎^πŸ’β–’βˆšπ’š π’…π’š = ∫_0^4β–’γ€–(𝑦)^(1/2) 𝑑𝑦〗 = [𝑦^(3/2)/(3/2)]_0^4 = 2/3 [𝑦^(3/2) ]_2^4 = 𝟐/πŸ‘ [(πŸ’)^(πŸ‘/𝟐 )βˆ’(𝟎)^(πŸ‘/𝟐) ] = 2/3 [(4)^(3/2 ) ] = 𝟐/πŸ‘ [𝟐^(𝟐 Γ—πŸ‘/𝟐) ]

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