CBSE Class 12 Sample Paper for 2026 Boards
CBSE Class 12 Sample Paper for 2026 Boards
Last updated at August 14, 2026 by Teachoo
Transcript
Question 34 (A) Solve the differential equation: 𝑦+𝑑/𝑑𝑥(𝑥𝑦)=𝑥(sin 𝑥+𝑥)Now, our equation is 𝑦+𝑑/𝑑𝑥(𝑥𝑦)=𝑥(sin 𝑥+𝑥) Using product formula 𝑦+(𝑑(𝑥))/𝑑𝑥 𝑦+𝑥 𝑑𝑦/𝑑𝑥=𝑥(sin 𝑥+𝑥) 𝑦+𝑦+𝑥 𝑑𝑦/𝑑𝑥=𝑥(sin 𝑥+𝑥) 𝑥 𝑑𝑦/𝑑𝑥+2𝑦=𝑥(sin 𝑥+𝑥) Diving both sides by x 𝑥/𝑥 \ × 𝑑𝑦/𝑑𝑥+2𝑦/𝑥=𝑥(sin 𝑥+𝑥)/𝑥 𝑑𝑦/𝑑𝑥+2𝑦/𝑥=(sin 𝑥+𝑥) Comparing with 𝑑𝑦/𝑑𝑥 + Py = Q P = 𝟐/𝒙 & Q = (𝒔𝒊𝒏 𝒙+𝒙) Finding Integrating factor (IF) IF = e^∫1▒𝑝𝑑𝑥 = 𝒆^∫1▒〖𝟐/𝒙 𝒅𝒙〗 = e^(2∫1▒〖1/𝑥 𝑑𝑥〗) = 𝒆^(𝟐 𝒍𝒐𝒈|𝒙| ) = e^log〖𝑥^2 〗 = 𝒙^𝟐 Solution of differential equation is y × IF = ∫1▒〖𝑄.𝐼𝐹 𝑑𝑥〗 Putting values y × x2 = ∫1▒〖(𝒔𝒊𝒏 𝒙+𝒙) 𝒙^𝟐 𝒅𝒙 〗 yx2 = ∫1▒〖𝑠𝑖𝑛𝑥 × 𝑥^2 〗 𝑑𝑥+∫1▒𝒙^𝟑 𝒅𝒙 yx2 = ∫1▒〖𝑠𝑖𝑛𝑥 × 𝑥^2 〗 𝑑𝑥+𝑥^4/4+𝐶 yx2 = ∫1▒〖𝒙^𝟐 𝒔𝒊𝒏𝒙 〗 𝒅𝒙+𝒙^𝟒/𝟒+𝑪 Evaluating ∫1▒〖𝒙^𝟐 𝒔𝒊𝒏𝒙 〗 𝒅𝒙 separately ∫1▒〖𝑥^2 sin𝑥 〗 𝑑𝑥 We know that ∫1▒〖𝑓(𝑥) 𝑔(𝑥) 〗 𝑑𝑥=𝑓(𝑥) ∫1▒𝑔(𝑥) 𝑑𝑥−∫1▒(𝑓^′ (𝑥) ∫1▒𝑔(𝑥) 𝑑𝑥) 𝑑𝑥 Putting f(x) = x2 and g(x) = sin x ∫1▒〖𝑥^2 sin𝑥 〗 𝑑𝑥=𝒙^𝟐 ∫1▒𝐬𝐢𝐧𝒙 𝒅𝒙−∫1▒(𝒅(𝒙^𝟐 )/𝒅𝒙 ∫1▒〖𝒔𝒊𝒏𝒙 𝒅𝒙〗) 𝒅𝒙 = − 𝑥^2 cos𝑥 − ∫1▒〖2𝑥 × −cos〖𝑥 𝑑𝑥〗 〗 = − 𝑥^2 cos𝑥+2 ∫1▒〖𝒙 𝒄𝒐𝒔𝒙 〗 𝒅𝒙+𝐶 Applying by parts again in ∫1▒〖𝒙 𝒄𝒐𝒔𝒙 〗 = − 𝑥^2 cos𝑥+2 [𝒙∫1▒𝒄𝒐𝒔𝒙 𝒅𝒙−∫1▒(𝒅𝒙/𝒅𝒙 ∫1▒〖𝒄𝒐𝒔𝒙 𝒅𝒙〗) 𝒅𝒙]+𝐶 = − 𝑥^2 cos𝑥+2 [𝒙 𝒔𝒊𝒏 𝒙−∫1▒〖𝟏 × 𝒔𝒊𝒏 𝒙〗 𝒅𝒙]+𝐶 = − 𝑥^2 cos𝑥+2 [𝑥 𝑠𝑖𝑛 𝑥−∫1▒〖𝒔𝒊𝒏 𝒙〗 𝒅𝒙]+𝐶 = − 𝑥^2 cos𝑥+2 [𝑥 𝑠𝑖𝑛 𝑥−(−𝑐𝑜𝑠 𝑥) ]+𝐶 = − 𝒙^𝟐 𝒄𝒐𝒔𝒙+𝟐 [𝒙 𝒔𝒊𝒏 𝒙+𝐜𝐨𝐬𝒙 ]+𝑪 Putting value of ∫1▒〖𝑥^2 sin𝑥 〗 𝑑𝑥 in (1) yx2 = ∫1▒〖𝑥^2 𝑠𝑖𝑛𝑥 〗 𝑑𝑥+𝑥^4/4+𝐶 yx2 = − 𝒙^𝟐 𝒄𝒐𝒔𝒙+𝟐 [𝒙 𝒔𝒊𝒏 𝒙+𝐜𝐨𝐬𝒙 ]+𝒙^𝟒/𝟒+𝑪 Which is the required solution