Question 37 (iii) (Choice B) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at August 14, 2026 by Teachoo

Identify the possible practical value of 𝑥 (i.e., the number of bulbs - CBSE Class 12 Sample Paper for 2026 Boards

part 2 - Question 37 (iii) (Choice B) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

part 3 - Question 37 (iii) (Choice B) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 37 (iii) - Choice B Identify the possible practical value of 𝑥 (i.e., the number of bulbs that can realistically be produced and sold) that can maximize the profit, if the resources available and the expenditure on machines allows to produce minimum 10 but not more than 18 bulbs per hour. Also calculate the maximum profit.Now, P(𝑥) = −0.8𝑥^2+30𝑥−150 It says value of x is minium 10, and not more than 18 So, 10 ≤ x ≤ 18 We find P(10) and P(18) and check what is maximum Finding P(10) P(𝑥) = −0.8𝑥^2+30𝑥−150 P(10) = −0.8(10)^2 + 30 × 10−150 P(10) = −0.8 × 100+ 300−150 P(10) = −80+ 300−150 P(𝟏𝟎) = 𝟕𝟎 Finding P(18) P(𝑥) = −0.8𝑥^2+30𝑥−150 P(18) = −0.8(18)^2 + 30 × 18−150 P(18) = −0.8 × 324+540−150 P(18) = −259.2+ 300−150 P(𝟏𝟖) = 𝟏𝟑𝟎.𝟖 Thus, Maximum profit occurs for x = 18, i.e. 18 bulbs And, Maximum profit = ₹ 130.8

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