Question 37 (ii) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at August 14, 2026 by Teachoo

[Case Based] Find the critical points of 𝑃(𝑥) - Sample Paper 2025-26 - CBSE Class 12 Sample Paper for 2026 Boards

part 2 - Question 37 (ii) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 37 (ii) Find the critical points of 𝑃(𝑥).To find critical points, we find values of x where P’(x) = 0 Now, P(𝑥) = −0.8𝑥^2+30𝑥−150 Diff w.r.t x P’(𝑥) = 𝑑(−0.8𝑥^2 + 30𝑥 − 150" " )/𝑑𝑥 P’(𝑥) = −0.8 × 2𝑥+30 P’(𝑥) = −1.6𝑥+30 Putting P’(𝒙) = 0 −1.6𝑥+30=0 −1.6𝑥=−30 𝑥=30/1.6 𝑥=30/(16/10) 𝑥=30/16 × 10 𝑥=30/16 × 10 𝒙=𝟏𝟖.𝟕𝟓 Thus, 𝟏𝟖.𝟕𝟓 is the critical point of P(x)

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