If ๐‘“(๐‘ฅ+๐‘ฆ)=๐‘“(๐‘ฅ)๐‘“(๐‘ฆ) for all ๐‘ฅ,๐‘ฆโˆˆR and ๐‘“(5)=2,๐‘“^โ€ฒ (0)=3, then - CBSE Class 12 Sample Paper for 2026 Boards

part 2 - Question 24 - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 24 - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12 part 4 - Question 24 - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 24 If ๐‘“(๐‘ฅ+๐‘ฆ)=๐‘“(๐‘ฅ)๐‘“(๐‘ฆ) for all ๐‘ฅ,๐‘ฆโˆˆR and ๐‘“(5)=2,๐‘“^โ€ฒ (0)=3, then using the definition of derivatives, find ๐‘“^โ€ฒ (5).When it says using the definition of derivatives, it means using the formula fโ€™(x) = (๐’๐’Š๐’Ž)โ”ฌ(๐’‰โ†’๐ŸŽ)โกใ€–(๐’‡(๐’™ + ๐’‰) โˆ’ ๐’‡ (๐’™))/๐’‰ใ€— Putting x = 5 fโ€™(5) = (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–(๐‘“(5 + โ„Ž) โˆ’ ๐‘“(5))/โ„Žใ€— Using ๐‘“(๐‘ฅ+๐‘ฆ)=๐‘“(๐‘ฅ)๐‘“(๐‘ฆ) fโ€™(5) = (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–(๐‘“(5) ร— ๐‘“(โ„Ž) โˆ’ ๐‘“(5))/โ„Žใ€— fโ€™(5) = (๐’๐’Š๐’Ž)โ”ฌ(๐’‰โ†’๐ŸŽ)โกใ€–(๐’‡(๐Ÿ“) [๐’‡(๐’‰) โˆ’ ๐Ÿ])/๐’‰ใ€— Putting f(5) = 2 fโ€™(5) = (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–(2 ร— [๐‘“(โ„Ž) โˆ’ 1])/โ„Žใ€— fโ€™(5) = ๐Ÿ (๐’๐’Š๐’Ž)โ”ฌ(๐’‰โ†’๐ŸŽ)โกใ€–[๐’‡(๐’‰) โˆ’ ๐Ÿ]/๐’‰ใ€— Now, since fโ€™(x) = (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–(๐‘“(๐‘ฅ + โ„Ž) โˆ’ ๐‘“ (๐‘ฅ))/โ„Žใ€— Putting x = 0 fโ€™(0) = (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–(๐‘“(0 + โ„Ž) โˆ’ ๐‘“(0))/โ„Žใ€— fโ€™(0) = (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–(๐‘“(โ„Ž) โˆ’ ๐‘“(0))/โ„Žใ€— Putting fโ€™(0) = 3 3 = (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–(๐‘“(โ„Ž) โˆ’ ๐‘“(0))/โ„Žใ€— (๐’๐’Š๐’Ž)โ”ฌ(๐’‰โ†’๐ŸŽ)โกใ€–(๐’‡(๐’‰) โˆ’ ๐’‡(๐ŸŽ))/๐’‰ใ€— = 3 Putting (2) in (1) fโ€™(5) = 2 (๐‘™๐‘–๐‘š)โ”ฌ(โ„Žโ†’0)โกใ€–[๐‘“(โ„Ž) โˆ’ 1]/โ„Žใ€— fโ€™(5) = 2 ร— 3 fโ€™(5) = ๐Ÿ”

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