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Chapter 8 Class 12 Application of Integrals

Master Chapter 8 Class 12 Application of Integrals with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.

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Updated for 2023-2024 NCERT!

Learn Chapter 8 Application of Integrals (AOI) of Class 12 free with solutions of all NCERT Questions for CBSE Maths. We will learn how to find area using Integration in this chapter.

We will use what we have studied in the last chapter, Chapter 7 Integration to solve questions.

 

The topics covered in the chapter include

  • Area of simple curves - Using ∫ x dy and  ∫ y dx
  •  Area bounded by curve and a horizontal or vertical line - Example: Area of curve y = x2 and line y = 4
  • Area between curve and line - Example: Area of circle x2 + y2 = 32, and line y = x
  • Area between two or three curves - Example: Area of region enclosed between  x2 + y2 = 4 and (x – 2)2 + y2 = 4.

Serial order wise

Ex 8.1 Start Learning
Examples Start Learning
Miscellaneous Start Learning
Case Based Questions (MCQ) Start Learning
Area between 2 curves Start Learning

Concept wise

Area under curve Start Learning
Area bounded by curve and horizontal or vertical line Start Learning
Area between curve and line Start Learning
Area between curve and curve Start Learning

Why Learn This With Teachoo?

Updated for 2023-2024 NCERT!

Learn Chapter 8 Application of Integrals (AOI) of Class 12 free with solutions of all NCERT Questions for CBSE Maths. We will learn how to find area using Integration in this chapter.

We will use what we have studied in the last chapter, Chapter 7 Integration to solve questions.

 

The topics covered in the chapter include

  • Area of simple curves - Using ∫ x dy and  ∫ y dx
  •  Area bounded by curve and a horizontal or vertical line - Example: Area of curve y = x2 and line y = 4
  • Area between curve and line - Example: Area of circle x2 + y2 = 32, and line y = x
  • Area between two or three curves - Example: Area of region enclosed between  x2 + y2 = 4 and (x – 2)2 + y2 = 4.