This question is similar to Chapter 5 Class 12 Continuity and Differentiability - Ex 5.5

Please check the question here 

https://www.teachoo.com/3677/701/Ex-5.5--11---Differentiate-(x-cos-x)x---(x-sin-x)1-x/category/Ex-5.5/

 

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Transcript

Question 23 (B) Differentiate the following function with respect to x:(cos 𝑥)^𝑥; (where ├ 𝑥∈(0,𝜋/2)).Let 𝑦 = 〖(𝑐𝑜𝑠⁡𝑥 ) 〗^𝑥 We use log differentiation Taking log both sides . log⁡𝑦 = log〖 (𝑐𝑜𝑠⁡𝑥 ) 〗^𝑥 𝒍𝒐𝒈⁡𝒚 = 𝒙 . 𝒍𝒐𝒈 (𝒄𝒐𝒔⁡𝒙 ) Differentiating both sides 𝑤.𝑟.𝑡.𝑥. (As 𝑙𝑜𝑔⁡(𝑎^𝑏 )=𝑏 . 𝑙𝑜𝑔⁡𝑎) 𝑑(log⁡𝑦 )/𝑑𝑥 = (𝑑(𝑥 . log⁡(cos⁡𝑥 ) ) )/𝑑𝑥 𝑑(log⁡𝑦 )/𝑑𝑦 . 𝑑𝑦/𝑑𝑥 = (𝑑(𝑥 . log⁡(cos⁡𝑥 ) ) )/𝑑𝑥 1/𝑦 (𝑑𝑦/𝑑𝑥) = (𝑑(𝑥 . log⁡(cos⁡𝑥 ) ) )/𝑑𝑥 1/𝑦 (𝑑𝑦/𝑑𝑥) = 𝑑𝑥/𝑑𝑥 log⁡〖( 𝑐𝑜𝑠 𝑥)〗+𝑥 (𝑑(𝑙𝑜𝑔⁡(𝑐𝑜𝑠⁡𝑥 ) ) )/𝑑𝑥 1/𝑦 (𝑑𝑦/𝑑𝑥) = log⁡〖(cos⁡𝑥)〗+𝑥 × 1/cos⁡𝑥 × (𝑐𝑜𝑠 𝑥)^′ 1/𝑦 (𝑑𝑦/𝑑𝑥) = log⁡〖(cos⁡𝑥)〗+𝑥/cos⁡𝑥 × (−sin⁡𝑥 ) Using product Rule As (𝑢𝑣)’ = 𝑢’𝑣 + 𝑣’𝑢 1/𝑦 (𝑑𝑦/𝑑𝑥) = log⁡〖(cos⁡𝑥)〗−𝑥 tan⁡𝑥 𝑑𝑦/𝑑𝑥 = 𝑦[log⁡(cos⁡𝑥 )−𝑥 tan⁡𝑥 ] Putting value of 𝑦 𝒅𝒚/𝒅𝒙 = (𝐜𝐨𝐬⁡𝒙 )^𝒙 [𝒍𝒐𝒈⁡(𝒄𝒐𝒔⁡𝒙 )−𝒙 𝒕𝒂𝒏⁡𝒙 ]

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.