[Video] Question 15 - The graph drawn below depicts (A) y = sin-1 x - CBSE Class 12 Sample Paper for 2025 Boards

part 2 - Question 15 - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 15 The graph drawn below depicts (A) ๐‘ฆ=ใ€–๐‘ ๐‘–๐‘›ใ€—^(โˆ’1) ๐‘ฅ (B) ๐‘ฆ=ใ€–๐‘๐‘œ๐‘ ใ€—^(โˆ’1) ๐‘ฅ (C) ๐‘ฆ=ใ€–๐‘๐‘œ๐‘ ๐‘’๐‘ใ€—^(โˆ’1) ๐‘ฅ (D) ๐‘ฆ=ใ€–๐‘๐‘œ๐‘กใ€—^(โˆ’1) ๐‘ฅ We can solve this using options From graph For x = โˆ’1, y = ๐œ‹ For x = 0, y = ๐œ‹/2 For x = 1, y = 0 Checking all options for x = โˆ’1, 0, 1 For x = โˆ’1 Option (A) - y So, the correct answer is (B) Question 15 The graph drawn below depicts (A) y=sin^(โˆ’1) x (B) ๐‘ฆ=ใ€–๐‘๐‘œ๐‘ ใ€—^(โˆ’1) ๐‘ฅ (C) ๐‘ฆ=ใ€–๐‘๐‘œ๐‘ ๐‘’๐‘ใ€—^(โˆ’1) ๐‘ฅ (D) ๐‘ฆ=ใ€–๐‘๐‘œ๐‘กใ€—^(โˆ’1) ๐‘ฅ We can solve this using options From graph For x = โˆ’1, y = ๐œ‹ For x = 0, y = ๐œ‹/2 For x = 1, y = 0 If we do normal trigonometry, then this basically means, For ฮธ = ๐œ‹, then __ ฮธ = โˆ’1 For ฮธ = ๐œ‹/2, then __ ฮธ = 0 For ฮธ = 0, then __ ฮธ = 1 Since cos 0 = 1 And, cos ๐œ‹/2 = 0 โˆด This is graph of ๐’š=ใ€–๐’„๐’๐’”ใ€—^(โˆ’๐Ÿ) ๐’™ So, the correct answer is (B)

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