Question 36 (ii) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at August 14, 2026 by Teachoo

Question 36 (ii) - Find 𝑑𝑉/𝑑𝑥 - Sample Paper Class 12 - Maths 2025 - CBSE Class 12 Sample Paper for 2025 Boards

part 2 - Question 36 (ii) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 36 (ii) Find 𝑑𝑉/𝑑𝑥Now, V = 2(2𝑥^3−65𝑥^2+500𝑥) Diff w.r.t 𝑥 V’(𝑥)=2𝑑[2𝑥^3 − 65𝑥^2 + 500𝑥]/𝑑𝑥 = 2[6𝑥^2−65 × 2𝑥+500] = 2[6𝑥^2−130𝑥+500] = 2 × 2[3𝑥^2−65𝑥+250] = 4[𝟑𝒙^𝟐−𝟔𝟓𝒙+𝟐𝟓𝟎] Splitting the middle term Splitting the middle term method We need to find two numbers whose Sum = –65 Product = 3 × 250 = 750 = 4[3𝑥^2−50𝑥−15𝑥+250] = 4[𝑥(3𝑥−50)−5(3𝑥−50)] = 4[(𝑥−5)(3𝑥−50)] = 4(𝒙−𝟓)(𝟑𝒙−𝟓𝟎)

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