Question 36 (ii) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at Dec. 13, 2024 by Teachoo

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Question 36 (ii) Find 𝑑𝑉/𝑑𝑥Now, V = 2(2𝑥^3−65𝑥^2+500𝑥) Diff w.r.t 𝑥 V’(𝑥)=2𝑑[2𝑥^3 − 65𝑥^2 + 500𝑥]/𝑑𝑥 = 2[6𝑥^2−65 × 2𝑥+500] = 2[6𝑥^2−130𝑥+500] = 2 × 2[3𝑥^2−65𝑥+250] = 4[𝟑𝒙^𝟐−𝟔𝟓𝒙+𝟐𝟓𝟎] Splitting the middle term Splitting the middle term method We need to find two numbers whose Sum = –65 Product = 3 × 250 = 750 = 4[3𝑥^2−50𝑥−15𝑥+250] = 4[𝑥(3𝑥−50)−5(3𝑥−50)] = 4[(𝑥−5)(3𝑥−50)] = 4(𝒙−𝟓)(𝟑𝒙−𝟓𝟎)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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