Question 37 (iii) (B) - If the track of the final race (for biker b1) - CBSE Class 12 Sample Paper for 2025 Boards

part 2 - Question 37 (iii) (B) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 37 (iii) (B) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12 part 4 - Question 37 (iii) (B) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12 part 5 - Question 37 (iii) (B) - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

 

Remove Ads Share on WhatsApp

Transcript

Question 37 (iii) (B) If the track of the final race (for the biker š‘_1) follows the curve š‘„^2=4š‘¦; ( where 0ā‰¤š‘„ā‰¤20√2. & 0ā‰¤š‘¦ā‰¤200), then state whether the track represents a one-one and onto function or not. (Justify).Given š‘„^2=4š‘¦ š‘¦=š‘„^2/4 Let š‘¦=š’‡(š’™)=š’™^šŸ/šŸ’ In [0, 20√2]→[0, 200] š’‡(š’™)=š’™^šŸ/šŸ’ Checking one-one š’‡(š’™_šŸ )=ć€–š’™_šŸć€—^šŸ/šŸ’ š’‡(š’™_šŸ )=ć€–š’™_šŸć€—^šŸ/šŸ’ Putting š’‡(š’™_šŸ )= š’‡(š’™_šŸ ) ć€–š’™_šŸć€—^šŸ/šŸ’= ć€–š’™_šŸć€—^šŸ/šŸ’ ć€–š’™_šŸć€—^šŸ = ć€–š’™_šŸć€—^šŸ x1 = x2 or x1 = –x2 But x1 = –x2 is not possible in our domain [0, 20√2] Rough One-one Steps: 1. Calculate f(x1) 2. Calculate f(x2) 3. Putting f(x1) = f(x2) we have to prove x1 = x2 So, x1 = x2 when f (x1) = f (x2) ∓ f(x) is one-one Check onto š’‡(š’™)=š’™^šŸ/šŸ’ Let f(x) = y , such that y ∈ R š‘„^2/4=š‘¦ š‘„^2=4š‘¦ š‘„=±2āˆšš‘¦ Since 0ā‰¤š‘¦ā‰¤200 and where 0ā‰¤š‘„ā‰¤20√2 For all values of y in [0, 200], there is a corresponding value of x in [0, 20√2] Thus, for every y in [0, 200], there exists a pre-image in [0, 20√2] ∓ f(x) is onto Thus, for every y in [0, 200], there exists a pre-image in [0, 20√2] ∓ f(x) is onto Let f(x) = y , such that y ∈ R x2 = y x = Ā±āˆšš‘¦ Note that y is a real number, so it can be negative also Putting y = āˆ’3 x = ±√((āˆ’3)) š‘¤ā„Žš‘–š‘ā„Ž š‘–š‘  š‘›š‘œš‘” š‘š‘œš‘ š‘ š‘–š‘š‘™š‘’ š‘Žš‘  š‘Ÿš‘œš‘œš‘” š‘œš‘“ š‘›š‘’š‘”š‘Žš‘”š‘–š‘£š‘’ š‘›š‘¢š‘šš‘š‘’š‘Ÿ š‘–š‘  š‘›š‘œš‘” š‘Ÿš‘’š‘Žš‘™ Hence, x is not real So, f is not onto

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo