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Question 5 The value of ' 𝑛 ', such that the differential equation 𝑥^𝑛 𝑑𝑦/𝑑𝑥=𝑦(log 𝑦−log 𝑥+1); (where 𝑥,𝑦∈𝑅^+) is homogeneous, is (A) 0 (B) 1 (C) 2 (D) 3To check homogeneous, we follow these steps Step 1 - Find dy/dx Step 2 - Putting F(x , y) = 𝑑𝑦/𝑑𝑥 and finding F(𝜆x, 𝜆y) If F(𝜆x, 𝜆y) = F(x, y), then it’s a homogenous equation Now, Step 1: Find 𝑑𝑦/𝑑𝑥 𝑥^𝑛 𝑑𝑦/𝑑𝑥=𝑦(log 𝑦−log 𝑥+1) 𝒅𝒚/𝒅𝒙=𝒚/𝒙^𝒏 (𝒍𝒐𝒈 𝒚−𝒍𝒐𝒈 𝒙+𝟏) Step 2: Putting F(x , y) = 𝑑𝑦/𝑑𝑥 and finding F(𝜆x, 𝜆y) F(x, y) = 𝒚/𝒙^𝒏 (𝒍𝒐𝒈 𝒚−𝒍𝒐𝒈 𝒙+𝟏) Finding F(𝝀x, 𝝀y) F(𝜆x, 𝜆y) = 𝝀𝒚/((〖𝝀𝒙)〗^𝒏 )(𝐥𝐨𝐠⁡𝝀𝒚−𝐥𝐨𝐠⁡𝝀𝒙+𝟏) Using log AB = log A + log B = 𝝀/𝝀^𝑛 ×𝒚/𝒙^𝒏 (log⁡𝝀+log⁡𝑦−(log⁡𝝀+log⁡𝑥 )+1) = 𝝀/𝝀^𝑛 ×𝒚/𝒙^𝒏 (log⁡𝝀+log⁡𝑦−log⁡𝝀−log⁡𝑥+1) = 𝝀/𝝀^𝑛 ×𝒚/𝒙^𝒏 (log⁡𝑦−log⁡𝑥+1) Now, F(𝜆x, 𝜆y) = F(x, y) is possible for n = 1 only Thus, for n = 1, the equation is homogeneous So, the correct answer is (B)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.