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Assertion (A): Consider function defined as 𝑓(π‘₯) = |π‘₯| + |π‘₯ βˆ’ 1| - CBSE Class 12 Sample Paper for 2025 Boards

part 2 - Question 19 [Assertion Reasoning] - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 19 [Assertion Reasoning] - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12 part 4 - Question 19 [Assertion Reasoning] - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12 part 5 - Question 19 [Assertion Reasoning] - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 19 Statement A Assertion (A): Consider the function defined as 𝑓(π‘₯)=|π‘₯|+|π‘₯βˆ’1|,π‘₯βˆˆπ‘…. Then 𝑓(π‘₯) is not differentiable at 𝒙=𝟎 and 𝒙=𝟏. Statement R Reason (R): Suppose 𝑓 be defined and continuous on (π‘Ž,𝑏) and π‘βˆˆ(π‘Ž,𝑏), then 𝑓(π‘₯) is not differentiable at π‘₯=𝑐 if lim_(β„Žβ†’0^βˆ’ )β€Š(𝑓(𝑐+β„Ž)βˆ’π‘“(𝑐))/β„Žβ‰ lim_(β„Žβ†’0^+ )β€Š(𝑓(𝑐 + β„Ž)βˆ’π‘“(𝑐))/β„Ž. (A) Both (A) and (R) are true and (R) is the correct explanation of (A). (B) Both (A) and ( 𝑅 ) are true but (𝑅) is not the correct explanation of (𝐴). (C) (A) is true but (R) is false. (D) (A) is false but (𝑅) is true.Checking Assertion Assertion (A): Consider the function defined as 𝑓(π‘₯)=|π‘₯|+|π‘₯βˆ’1|,π‘₯βˆˆπ‘…. Then 𝑓(π‘₯) is not differentiable at 𝒙=𝟎 and 𝒙=𝟏. Given 𝑓(π‘₯)= |π‘₯|+ |π‘₯βˆ’1|. Here, we have 2 critical points x = 0 and x βˆ’ 1 = 0 i.e. x = 0, and x = 1 Let’s draw its graph From graph, we can see that At x = 0 and x = 1, It is an edge point And, the function is not differentiable at edge points. Since at x = 0, and x = 1 is not differentiable ∴ Assertion is true Checking Reason Reason (R): Suppose 𝑓 be defined and continuous on (π‘Ž,𝑏) and π‘βˆˆ(π‘Ž,𝑏), then 𝑓(π‘₯) is not differentiable at π‘₯=𝑐 if lim_(β„Žβ†’0^βˆ’ )β€Š(𝑓(𝑐+β„Ž)βˆ’π‘“(𝑐))/β„Žβ‰ lim_(β„Žβ†’0^+ )β€Š(𝑓(𝑐 + β„Ž)βˆ’π‘“(𝑐))/β„Ž.. Here, reasoning is describing the differentiability test lim_(β„Žβ†’0^βˆ’ )β€Š(𝑓(𝑐+β„Ž)βˆ’π‘“(𝑐))/β„Ž is Left hand derivative at x = c lim_(β„Žβ†’0^+ )β€Š(𝑓(𝑐 + β„Ž)βˆ’π‘“(𝑐))/β„Ž is Right hand derivative at x = c And, since the function is not differentiable at x = c, LHD β‰  RHD This is true Hence, Reason is true Is Reason a Correct explanation for Assertion? Since Derivative test can be used to check differentiability at x = 0, and x = 1 Thus, we used the concept mentioned in Reasoning to check Assertion Therefore, Reasoning is a correct explanation for Assertion So, Assertion is true Reasoning is true And, Reasoning is a correct explanation for Assertion So, the correct answer is (a)

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