Question 21

If cot^(-1) (3x+5)>ฯ€/4, then find the range of the values of x.

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Question 21 - If cot-1 (3x + 5) >๐œ‹/4, then find range of values of x - CBSE Class 12 Sample Paper for 2025 Boards

part 2 - Question 21 - CBSE Class 12 Sample Paper for 2025 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Transcript

Question 21 If cot^(โˆ’1) (3๐‘ฅ+5)>๐œ‹/4, then find the range of the values of ๐‘ฅ.Given ใ€–๐‘๐‘œ๐‘กใ€—^(โˆ’1) (3๐‘ฅ+5)>๐œ‹/4 Taking cot^(โˆ’1) on other side, Sign of inequality changes because cot^(โˆ’1) is a decreasing function ๐Ÿ‘๐’™+๐Ÿ“<๐’„๐’๐’•โกใ€–๐…/๐Ÿ’ใ€— Putting ๐‘๐‘œ๐‘กโกใ€–๐œ‹/4ใ€— = 1 3๐‘ฅ+5<1 3๐‘ฅ<1โˆ’5 3๐‘ฅ<โˆ’4 Note: Here cot^(โˆ’1) is a decreasing function. This means As x increases cot^(โˆ’1) decreases For example ใ€–๐’„๐’๐’•ใ€—^(โˆ’๐Ÿ) โˆš๐Ÿ‘<ใ€–๐’„๐’๐’•ใ€—^(โˆ’๐Ÿ) ๐Ÿ as 30ยฐ < 45ยฐ But, if we remove ใ€–๐’„๐’๐’•ใ€—^(โˆ’๐Ÿ) โˆš๐Ÿ‘>๐Ÿ So, when we remove cot^(โˆ’1), we have to change the sign of inequality ๐’™<(โˆ’๐Ÿ’)/๐Ÿ‘ So, ๐’™ โˆˆ(โˆ’โˆž,(โˆ’๐Ÿ’)/๐Ÿ‘)

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