CBSE Class 12 Sample Paper for 2024 Boards

CBSE Class 12 Sample Paper for 2023 Boards →
Class 12
Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Question 21 (Choice 1) - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at February 10, 2025 by

Find the value of γ€–sinγ€—^(-1) [cos(33Ο€/5)]

This question is similar to Example-9 Chapter-2 Inverse trigonometry

1.jpg

2.jpg
3.jpg

Β 

Remove Ads Share on WhatsApp

Transcript

sinβˆ’1 ("cos " 33Ο€/6) = sinβˆ’1 ("cos " (πŸ”π…+πŸ‘π…/πŸ“)) = sinβˆ’1 ("cos " 3πœ‹/5) = sinβˆ’1 ("sin" (𝝅/𝟐 βˆ’πŸ‘π›‘/πŸ“)) = sinβˆ’1 ("sin" ((5πœ‹ βˆ’ 6πœ‹)/10 )) = sinβˆ’1 ("sin" ((βˆ’π…)/𝟏𝟎 )) Let y = sinβˆ’1 ("sin" ((βˆ’πœ‹)/10 )) sin y = "sin" ((βˆ’πœ‹)/10 ) sin y = sin (-18Β°) Hence, y = (βˆ’π…)/𝟏𝟎 Which is in the range of sin-1 i.e. [(βˆ’π›‘)/𝟐, 𝛑/𝟐] Hence, γ€–π’”π’Šπ’γ€—^(βˆ’πŸ) [𝒄𝒐𝒔(πŸ‘πŸ‘π…/πŸ”)] = (βˆ’π…)/𝟏𝟎 Hence, γ€–π’”π’Šπ’γ€—^(βˆ’πŸ) [𝒄𝒐𝒔(πŸ‘πŸ‘π…/πŸ”)] = (βˆ’π…)/𝟏𝟎

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo