Question 15 - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at Dec. 13, 2024 by Teachoo

The general solution of the differential equation 𝑦𝑑𝑥 − 𝑥𝑑𝑦 = 0 ; (Given x,y >0) is of the form

(a) 𝑥𝑦 = 𝐶 (b) 𝑥 = 〖Cy〗^2 (c) 𝑦 = 𝐶𝑥 (d) 𝑦 = Cx^2

(Where ‘c’ is an arbitrary positive constant of integration)

This question is exactly same as Question-15 CBSE Class 12 Sample Paper for 2023 Boards

Please check https://www.teachoo.com/19121/4115/Question-15/category/CBSE-Class-12-Sample-Paper-for-2023-Boards/

[MCQ] The general solution of differential equation ydx - xdy = 0 is - CBSE Class 12 Sample Paper for 2024 Boards

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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