The value of |A|, if A=[0 2x-1 √x 1-2x 0 2√x -√x -2√x 0)], where x∈R^+, is

(a) (2x+1)^2Β Β Β Β Β Β Β Β  (b) 0Β Β Β Β Β Β Β Β Β Β Β Β  (c) (2x+1)^3Β Β Β Β Β Β Β Β Β Β Β  (d) (2x-1)^2

[Determinants Class 12 - MCQ] The value of |A|, if A = [0 2x-1 √x 1-2x - CBSE Class 12 Sample Paper for 2024 Boards

part 2 - Question 10 - CBSE Class 12 Sample Paper for 2024 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Transcript

Given 𝐴=[β– (0&2π‘₯βˆ’1&√π‘₯@1βˆ’2π‘₯&0&2√π‘₯@βˆ’βˆšπ‘₯&βˆ’2√π‘₯&0)] Since diagonal elements are 0, this might be a skew symmetric matrix Let’s check Finding 𝑨^𝑻 𝐴^𝑇=[β– (0&1βˆ’2π‘₯&βˆ’βˆšπ‘₯@2π‘₯βˆ’1&0&βˆ’2√π‘₯@√π‘₯&2√π‘₯&0)] 𝐴^𝑇=βˆ’[β– (0&2π‘₯βˆ’1&√π‘₯@1βˆ’2π‘₯&0&2√π‘₯@βˆ’βˆšπ‘₯&βˆ’2√π‘₯&0)] 𝑨^𝑻= βˆ’ A Since 𝐴^𝑇= βˆ’A ∴ A is a skew symmetric matrix of order 3 We know that , Determinant of every skew symmetric matrix of odd order is 0. ∴ |A| = 0 So, the correct answer is (b)

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