Question 36 (i) [Case Based] - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at Dec. 13, 2024 by Teachoo

The temperature of a person during an intestinal illness is given by 𝑓(𝑥) = −0.1x^2 + 𝑚𝑥 + 98, 0 ≤x≤12, m being a constant, where 𝑓(𝑥) is the temperature in °F at x days

Question 36 Class 12 - Teachoo.jpg

Based on the above information answer the following questions.

Question 36 ( i )

Is the function differentiable in the interval (0, 12)? Justify your answer.

part 2 - Question 36 (i) [Case Based] - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

part 3 - Question 36 (i) [Case Based] - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

Next: Question 36 (ii) → Share on WhatsApp

Transcript

Question 36 [Case Based] The temperature of a person during an intestinal illness is given by 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98, 0 ≤𝑥≤12, m being a constant, where 𝑓(𝑥) is the temperature in °F at x daysBased on the above information answer the following questions. Question 36 (i) Is the function differentiable in the interval (0, 12)? Justify your answer.In interval (0, 12) The function is 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98 Since it is a polynomial function And polynomial functions are differentiable everywhere ∴ f(x) is differentiable in (0, 12)

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

Class 6

Class 7

Class 8

Class 9

Class 10

Class 11

Class 12

Courses

Interesting

Popular