If y√1-x 2 +x√1-y 2 =1, then prove that dy/dx=-√1 - y 2 /1 - x 2

[Class 12 Sample Paper] If y√1-x^2 + x√1-y^2, then prove that dy/dx = - CBSE Class 12 Sample Paper for 2023 Boards
part 2 - Question 24 - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 24 - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 24 If π‘¦βˆš(1βˆ’π‘₯^2 )+π‘₯√(1βˆ’π‘¦^2 )=1, then prove that dy/dx=βˆ’βˆš((1 βˆ’ 𝑦^2)/(1 βˆ’ π‘₯^2 )) Finding π’…π’š/𝒅𝒙 would be complicated here To make life easy, we substitute x = sin A y = sin B (As √(1βˆ’π‘₯^2 )= √(1βˆ’sin^2⁑𝐴 )=√(cos^2⁑𝐴 )) And then solve Let’s substitute x = sin A y = sin B in our equation Now π‘¦βˆš(1βˆ’π‘₯^2 ) + π‘₯√(1βˆ’π‘¦^2 ) = 1 Putting x = sin A and y = sin B 𝐬𝐒𝐧 𝐁√(πŸβˆ’γ€–π¬π’π§γ€—^πŸβ‘π‘¨ ) + 𝐬𝐒𝐧 π€βˆš(πŸβˆ’γ€–π’”π’Šπ’γ€—^πŸβ‘π‘© ) = 1 sin B√(cos^2⁑𝐴 ) + sin A√(cos^2⁑𝐡 ) = a (sin A βˆ’ sin B) sin B cos A + sin A cos B = 1 sin A cos B + sin B cos A = 1 sin (A + B) = 1 sin (A + B) = sin 𝝅/𝟐 A + B = 𝝅/𝟐 Putting back values of A and B sin^(βˆ’1)⁑π‘₯+sin^(βˆ’1)⁑𝑦=πœ‹/2 Differentiating w.r.t x 1/√(1 βˆ’ π‘₯^2 )βˆ’1/√(1 βˆ’ 𝑦^2 )×𝑑𝑦/𝑑π‘₯=0 1/√(1 βˆ’ π‘₯^2 )=1/√(1 βˆ’ 𝑦^2 )×𝑑𝑦/𝑑π‘₯ √(1 βˆ’ 𝑦^2 )/√(1 βˆ’ π‘₯^2 )=𝑑𝑦/𝑑π‘₯ π’…π’š/(𝒅𝒙 ) = √(𝟏 βˆ’ π’š^𝟐 )/√(𝟏 βˆ’ 𝒙^𝟐 )

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo