Find the direction ratio and direction cosines of a line parallel to the line whose equations are 6š‘„ āˆ’ 12 = 3š‘¦ + 9 = 2š‘§ āˆ’ 2

[Sample paper] Find the direction ratio and direction cosines of a - CBSE Class 12 Sample Paper for 2023 Boards
part 2 - Question 23 (Choice 2) - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 23 (Choice 2) Find the direction ratio and direction cosines of a line parallel to the line whose equations are 6š‘„ āˆ’ 12 = 3š‘¦ + 9 = 2š‘§ āˆ’ 2 Given equation of line 6š‘„ āˆ’ 12 = 3š‘¦ + 9 = 2š‘§ āˆ’ 2 6(š‘„ āˆ’ 2) = 3(š‘¦ + 3) = 2(š‘§ āˆ’ 1) Dividing both sides by 6 (6(š‘„ āˆ’ 2))/6=(3(š‘¦ + 3))/6=(2(š‘§ āˆ’ 1))/6 ((š’™ āˆ’ šŸ))/šŸ=((š’š + šŸ‘))/šŸ=((š’› āˆ’ šŸ))/šŸ‘ Thus, Direction ratios of the line parallel to the line = 1, 2, 3 ∓ š‘Ž = 1, b = 2, c = 3 Also, √(š’‚^šŸ + š’ƒ^šŸ + š’„^šŸ ) = √(12 +22 +32) = √(1 +4 +9) = āˆššŸšŸ’ Direction cosines = š‘Ž/√(š‘Ž^2 + š‘^2 + š‘^2 ) , š‘/√(š‘Ž^2 + š‘^2 + š‘^2 ) , š‘/√(š‘Ž^2 + š‘^2 + š‘^2 ) = šŸ/āˆššŸšŸ’ , šŸ/āˆššŸšŸ’ , šŸ‘/āˆššŸšŸ’

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo