The scalar projection of the vector 3i ฬ‚-j ฬ‚-2k ฬ‚ ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ i ฬ‚+2j ฬ‚-3k ฬ‚ is

(a) 7/โˆš14 ย 

(b) 7/14 ย 

(c) 6/13 ย 

(d) 7/2

ย 

[MCQ] The scalar projection of vector 3i - j - 2k on vector i+2j-3k is - CBSE Class 12 Sample Paper for 2023 Boards

part 2 - Question 8 - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 8 The scalar projection of the vector 3๐‘– ฬ‚โˆ’๐‘— ฬ‚โˆ’2๐‘˜ ฬ‚ ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ ๐‘– ฬ‚+2๐‘— ฬ‚โˆ’3๐‘˜ ฬ‚ is (a) 7/โˆš14 (b) 7/14 (c) 6/13 (d) 7/2 Let a = 3๐‘– ฬ‚ โˆ’ ๐‘— ฬ‚ โˆ’ 2๐‘˜ ฬ‚ and b = ๐‘– ฬ‚ + 2๐‘— ฬ‚ โˆ’ 3๐‘˜ ฬ‚ We need to find Projection of ๐‘Ž โƒ— on ๐‘ โƒ— We know that Projection of ๐‘Ž โƒ— on ๐‘ โƒ— = ๐Ÿ/("|" ๐’ƒ โƒ—"|" ) (๐’‚ โƒ—. ๐’ƒ โƒ—) Now, (๐’‚ โƒ—. ๐’ƒ โƒ—) = (3๐‘– ฬ‚ โˆ’ ๐‘— ฬ‚ โˆ’ 2๐‘˜ ฬ‚ ) . (๐‘– ฬ‚ + 2๐‘— ฬ‚ โˆ’ 3๐‘˜ ฬ‚) = (3 ร— 1) + (โ€“1 ร— 2) + (โˆ’2 ร— โˆ’3) = 7 Magnitude of ๐‘ โƒ— = โˆš(12+22+(โˆ’3) 2) |๐’ƒ โƒ— | = โˆš(1+4+9) = โˆš๐Ÿ๐Ÿ’ Thus, Projection of ๐’‚ โƒ— on ๐’ƒ โƒ— = 1/("|" ๐‘ โƒ—"|" ) (๐‘Ž โƒ—. ๐‘ โƒ—) = ๐Ÿ•/โˆš๐Ÿ๐Ÿ’ So, the correct answer is (a)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo