Ex 5.3, 12 - Find sum of first 40 integers divisible by 6

Ex 5.3, 12 - Chapter 5 Class 10 Arithmetic Progressions - Part 2

  1. Chapter 5 Class 10 Arithmetic Progressions (Term 2)
  2. Serial order wise

Transcript

Ex 5.3, 12 Find the sum of first 40 positive integers divisible by 6. Positive integers divisible by 6 are 6, 12, 18, 24,โ€ฆ. Since difference is same, it is an AP We need to find sum of first 40 integers We can use formula Sn = ๐‘›/2 (2a + (n โ€“ 1) d) Here, n = 40 , a = 6 & d = 12 โ€“ 6 = 6 Putting values in formula Sn = ๐’/๐Ÿ (2a + (n โ€“ 1) d) Sn = 40/2 (2 ร— 6 + (40 โˆ’ 1) ร— 6) Sn = 20 (12 + 39 ร— 6) Sn = 20 (12 + 234) Sn = 20 ร— 246 Sn = 4920 Therefore, the sum of first 40 integers divisible by 6 is 4920

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.