
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 5.3
Ex 5.3, 1 (ii)
Ex 5.3, 1 (iii) Important
Ex 5.3, 1 (iv)
Ex 5.3, 2 (i)
Ex 5.3, 2 (ii)
Ex 5.3, 2 (iii) Important
Ex 5.3, 3 (i)
Ex 5.3, 3 (ii)
Ex 5.3, 3 (iii)
Ex 5.3, 3 (iv) Important
Ex 5.3, 3 (v)
Ex 5.3, 3 (vi) Important
Ex 5.3, 3 (vii)
Ex 5.3, 3 (viii) Important
Ex 5.3, 3 (ix)
Ex 5.3, 3 (x)
Ex 5.3, 4
Ex 5.3, 5
Ex 5.3, 6 Important
Ex 5.3, 7
Ex 5.3, 8
Ex 5.3, 9
Ex 5.3, 10 (i)
Ex 5.3, 10 (ii) Important
Ex 5.3, 11 Important
Ex 5.3, 12 You are here
Ex 5.3, 13
Ex 5.3, 14 Important
Ex 5.3, 15
Ex 5.3, 16 Important
Ex 5.3, 17
Ex 5.3, 18 Important
Ex 5.3, 19 Important
Ex 5.3, 20 Important
Last updated at May 29, 2023 by Teachoo
Ex 5.3, 12 Find the sum of first 40 positive integers divisible by 6. Positive integers divisible by 6 are 6, 12, 18, 24,…. Since difference is same, it is an AP We need to find sum of first 40 integers We can use formula Sn = 𝑛/2 (2a + (n – 1) d) Here, n = 40 , a = 6 & d = 12 – 6 = 6 Putting values in formula Sn = 𝒏/𝟐 (2a + (n – 1) d) Sn = 40/2 (2 × 6 + (40 − 1) × 6) Sn = 20 (12 + 39 × 6) Sn = 20 (12 + 234) Sn = 20 × 246 Sn = 4920 Therefore, the sum of first 40 integers divisible by 6 is 4920