Ex 5.3, 1 (iii) - Chapter 5 Class 10 Arithmetic Progressions

Last updated at April 16, 2024 by

Ex 5.3, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 5

Ex 5.3, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 6

Go Ad-free

Transcript

Ex 5.3, 1 Find the sum of the following APs. (iii) 0.6, 1.7, 2.8 ,…….., to 100 terms 0.6, 1.7, 2.8,…… to 100 terms We know that Sum = 𝑛/2 (2a + (n – 1) d) Here n = 100, a = 0.6, & d = 1.7 – 0.6 = 1.1 Putting in formula Sum = 𝒏/𝟐 (2a + (n – 1) d) = 100/2 (2 × 0.6 + (100 – 1) × 1.1) = 50(1.2 + 99 × 1.1) = 50(1.2 + 108.9) = 50 (110.1) = 50 × 110 . 1 = 5505

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo