Ex 5.3, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 5

Ex 5.3, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 6

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Ex 5.3, 1 Find the sum of the following APs. (iii) 0.6, 1.7, 2.8 ,…….., to 100 terms 0.6, 1.7, 2.8,…… to 100 terms We know that Sum = 𝑛/2 (2a + (n – 1) d) Here n = 100, a = 0.6, & d = 1.7 – 0.6 = 1.1 Putting in formula Sum = 𝒏/𝟐 (2a + (n – 1) d) = 100/2 (2 × 0.6 + (100 – 1) × 1.1) = 50(1.2 + 99 × 1.1) = 50(1.2 + 108.9) = 50 (110.1) = 50 × 110 . 1 = 5505

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.