Ex 5.3, 1 Class 10 (NCERT Solutions) - Find sum of APs (i) 2, 7, 12,

Ex 5.3, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 2

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  1. Chapter 5 Class 10 Arithmetic Progressions (Term 2)
  2. Serial order wise

Transcript

Ex 5.3, 1 Find the sum of the following APs. (i) 2, 7, 12 ,…., to 10 terms. 2, 7, 12,…., to 10 term s We know that Sum of AP = 𝑛/2 (2a + (n – 1) d) Here n = 10, a = 2, & d = 7 – 2 = 2 Putting these in formula , Sum = 𝒏/𝟐 (2a + (n – 1) d) = 10/2 (2 Γ— 2 + (10 – 1) Γ— 5) = 5(3 + 9 Γ— 5) = 5 (4 + 45) = 5 (49) = 245

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.