Ex 5.3, 1 (i) - Chapter 5 Class 10 Arithmetic Progressions

Last updated at April 16, 2024 by

Ex 5.3, 1 Class 10 (NCERT Solutions) - Find sum of APs (i) 2, 7, 12,

Ex 5.3, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 2

 

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Ex 5.3, 1 Find the sum of the following APs. (i) 2, 7, 12 ,…., to 10 terms. 2, 7, 12,…., to 10 term s We know that Sum of AP = 𝑛/2 (2a + (n – 1) d) Here n = 10, a = 2, & d = 7 – 2 = 2 Putting these in formula , Sum = 𝒏/𝟐 (2a + (n – 1) d) = 10/2 (2 × 2 + (10 – 1) × 5) = 5(3 + 9 × 5) = 5 (4 + 45) = 5 (49) = 245

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo