Learn all Concepts of Chapter 5 Class 10 (with VIDEOS). Check - Arithmetic Progressions - Class 10

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 5.3 ,8 Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively. We know that an = a + (n 1) d From (1) & (2) 14 d = 18 2d 2d d = 18 14 d = 4 Putting value of d in (1) a = 14 d a = 14 4 a = 10 Now, we need to find sum of first 51 terms We can use formula Sn = /2 (2 a + (n 1) d) Here , n = 51 , a = 10 & d = 4 Putting values Sn = /2 (2a + (n 1) d) S51 = 51/2 (2 10+(51 1) 4) S51 = 51/2 (20 + 50 4) S51 = 51/2 (20+200) S51 = 51/2 220 S51 = 51 110 S51 = 5610 Hence the sum of first 51 terms is 5610

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Ex 5.3, 15 Not in Syllabus - CBSE Exams 2021

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Chapter 5 Class 10 Arithmetic Progressions

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.