

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 5.3
Ex 5.3, 1 (ii)
Ex 5.3, 1 (iii) Important
Ex 5.3, 1 (iv)
Ex 5.3, 2 (i)
Ex 5.3, 2 (ii)
Ex 5.3, 2 (iii) Important
Ex 5.3, 3 (i)
Ex 5.3, 3 (ii)
Ex 5.3, 3 (iii)
Ex 5.3, 3 (iv) Important
Ex 5.3, 3 (v)
Ex 5.3, 3 (vi) Important
Ex 5.3, 3 (vii) You are here
Ex 5.3, 3 (viii) Important
Ex 5.3, 3 (ix)
Ex 5.3, 3 (x)
Ex 5.3, 4
Ex 5.3, 5
Ex 5.3, 6 Important
Ex 5.3, 7
Ex 5.3, 8
Ex 5.3, 9
Ex 5.3, 10 (i)
Ex 5.3, 10 (ii) Important
Ex 5.3, 11 Important
Ex 5.3, 12
Ex 5.3, 13
Ex 5.3, 14 Important
Ex 5.3, 15
Ex 5.3, 16 Important
Ex 5.3, 17
Ex 5.3, 18 Important
Ex 5.3, 19 Important
Ex 5.3, 20 Important
Last updated at May 29, 2023 by Teachoo
Ex 5.3, 3 In an AP (vii) Given a = 8, an = 62, Sn = 210, find n and d. Given a = 8, an = 62, Sn = 210, Since there are n terms, π = an = 62 We use the formula Sn = π/π (π+π) Putting a = 8, Sn = 210, π = an = 62 210 = π/2 (8+62) 210 Γ 2=π Γ (70) 420 = n Γ 70 420/70=π 6 = n n = 6 Now we need to find d We can use formula an = a + (n β 1) d Putting an = 62, a = 8, n = 6 62 = 8 + (6 β 1) Γ π 62 = 8 + 5d 62 β 8 = 5d 54 = 5d d = ππ/π