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Ex 5.2
Ex 5.2, 2 (i) (MCQ)
Ex 5.2, 2 (ii) (MCQ) Important
Ex 5.2, 3 (i)
Ex 5.2, 3 (ii)
Ex 5.2, 3 (iii) Important
Ex 5.2, 3 (iv)
Ex 5.2, 3 (v) Important
Ex 5.2, 4
Ex 5.2, 5 (i)
Ex 5.2, 5 (ii) Important
Ex 5.2, 6 Important
Ex 5.2, 7
Ex 5.2, 8
Ex 5.2, 9
Ex 5.2, 10
Ex 5.2, 11
Ex 5.2, 12 Important
Ex 5.2, 13 Important
Ex 5.2, 14 Important
Ex 5.2, 15
Ex 5.2, 16
Ex 5.2, 17 Important
Ex 5.2, 18
Ex 5.2, 19
Ex 5.2, 20 Important
Last updated at May 29, 2023 by Teachoo
Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (i) Here, a = 7 , d = 3 , n = 8 Now, an = a + (n – 1) d Putting values = 7 + (8 – 1) × 3 = 7 + 7 × 3 = 7 + 21 = 28 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and anthe nth term of the A.P. (ii) Here, a = –18 , n = 10 , an = 0 an = a + (n – 1) d Putting values 0 = – 18 + (10 – 1) × d 0 = – 18 + (9) × d 0 + 18 = 9d 18/9 = d 2 = d d = 2 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (iii) Here, d = –3 , n = 18 , an = – 5 Now, an = a + (n – 1) d Putting values –5 = a + (18 – 1) × – 3 –5 = a + 17 × – 3 –5 = a – 51 –5 + 51 = a 46 = a a = 46 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (iv) Here, a = –18.9, d = 2.5 , an = 3.6 Now, an = a + (n – 1) d Putting values 3.6 = –18.9 + (n – 1) × 2.5 3.6 = –18.9 + 2.5 n – 2.5 3.6 = –21.4 + 2.5 n 3.6 + 21.4 = 2.5 n 25 = 2.5 n 25/2.5 = n 10 = n n = 10 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (v) Given a = 3.5, d = 0 , n = 105 Now, an = a + (n – 1) d Putting values = 3.5 + (105 – 1) × 0 = 3.5 + 104 × 0 = 3.5 + 0 = 3.5 Hence, an = 3.5