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Ex 5.2, 1 - Fill in the blanks, given that a is first term

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Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 2

Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 3

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Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 4

Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 5

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Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 6

Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 7

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Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 8

Ex 5.2, 1 - Chapter 5 Class 10 Arithmetic Progressions - Part 9

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Transcript

Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (i) Here, a = 7 , d = 3 , n = 8 Now, an = a + (n – 1) d Putting values = 7 + (8 – 1) × 3 = 7 + 7 × 3 = 7 + 21 = 28 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and anthe nth term of the A.P. (ii) Here, a = –18 , n = 10 , an = 0 an = a + (n – 1) d Putting values 0 = – 18 + (10 – 1) × d 0 = – 18 + (9) × d 0 + 18 = 9d 18/9 = d 2 = d d = 2 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (iii) Here, d = –3 , n = 18 , an = – 5 Now, an = a + (n – 1) d Putting values –5 = a + (18 – 1) × – 3 –5 = a + 17 × – 3 –5 = a – 51 –5 + 51 = a 46 = a a = 46 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (iv) Here, a = –18.9, d = 2.5 , an = 3.6 Now, an = a + (n – 1) d Putting values 3.6 = –18.9 + (n – 1) × 2.5 3.6 = –18.9 + 2.5 n – 2.5 3.6 = –21.4 + 2.5 n 3.6 + 21.4 = 2.5 n 25 = 2.5 n 25/2.5 = n 10 = n n = 10 Ex 5.2, 1 Fill in the blanks in the following table, given that a is the first term, d the common difference and an the nth term of the A.P. (v) Given a = 3.5, d = 0 , n = 105 Now, an = a + (n – 1) d Putting values = 3.5 + (105 – 1) × 0 = 3.5 + 104 × 0 = 3.5 + 0 = 3.5 Hence, an = 3.5

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.