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Ex 5.2
Ex 5.2, 2 (i) (MCQ)
Ex 5.2, 2 (ii) (MCQ) Important
Ex 5.2, 3 (i)
Ex 5.2, 3 (ii)
Ex 5.2, 3 (iii) Important
Ex 5.2, 3 (iv) You are here
Ex 5.2, 3 (v) Important
Ex 5.2, 4
Ex 5.2, 5 (i)
Ex 5.2, 5 (ii) Important
Ex 5.2, 6 Important
Ex 5.2, 7
Ex 5.2, 8
Ex 5.2, 9
Ex 5.2, 10
Ex 5.2, 11
Ex 5.2, 12 Important
Ex 5.2, 13 Important
Ex 5.2, 14 Important
Ex 5.2, 15
Ex 5.2, 16
Ex 5.2, 17 Important
Ex 5.2, 18
Ex 5.2, 19
Ex 5.2, 20 Important
Last updated at Aug. 3, 2021 by Teachoo
Ex 5.2, 3 In the following APs find the missing term in the boxes (iv) – 4, ⎕, ⎕, ⎕, ⎕, 6 Given, a = –4, a6 = 6 We know that an = a + (n – 1) d Putting values a6 = – 4 + (6 – 1) × d 6 = – 4 + 5 d 6 + 4 = 5d 10 = 5d 10/5 = d 2 = d d = 2 Now , a = –4, d = 2 We need to find a2, a3, a4, a5 a2 a2 = a + (2 – 1) d = a + d = –4 + 2 = –2 a3 a3 = a + (3 – 1) d = a + 2d = –4 + 2(2) = 0 a4 a4 = a + (4 – 1) d = a + 3d = –4 + 3(2) = 2 a5 a3 = a + (5 – 1)d = a + 4d = –4 + 4(2) = 4 Hence, – 4, , , , , 6