Ex 5.2, 5 (ii) - Chapter 5 Class 10 Arithmetic Progressions (Term 2)
Last updated at Aug. 3, 2021 by Teachoo
Transcript
Ex 5.2, 5 Find the number of terms in the following AP (ii) 18, 151/2, 13,……….,-47 18, 15 1/2 , 13, … 47 Here, an = – 47 a = 18 d = 15 1/2 – 18 = (15 × 2 + 1)/2 – 18 = 31/2 – 18 = (31 − 18 × 2)/2 = (31− 36)/2 = (−5)/2 We need to find n Putting values in formula an = a + (n – 1) d –47 = 18 + (n – 1) × ((−5)/2) –65 = (n – 1) × ((− 5)/2) (−65 × 2)/(−5) = (n – 1) 26 = n – 1 n – 1 = 26 n = 26 + 1 n = 27 Hence the number of terms in the given AP is 27
Ex 5.2
Ex 5.2, 1
Ex 5.2, 2 (i) (MCQ)
Ex 5.2, 2 (ii) (MCQ) Important
Ex 5.2, 3 (i)
Ex 5.2, 3 (ii)
Ex 5.2, 3 (iii) Important
Ex 5.2, 3 (iv)
Ex 5.2, 3 (v) Important
Ex 5.2, 4
Ex 5.2, 5 (i)
Ex 5.2, 5 (ii) Important You are here
Ex 5.2, 6 Important
Ex 5.2, 7
Ex 5.2, 8
Ex 5.2, 9
Ex 5.2, 10
Ex 5.2, 11
Ex 5.2, 12 Important
Ex 5.2, 13 Important
Ex 5.2, 14 Important
Ex 5.2, 15
Ex 5.2, 16
Ex 5.2, 17 Important
Ex 5.2, 18
Ex 5.2, 19
Ex 5.2, 20 Important
Chapter 5 Class 10 Arithmetic Progressions (Term 2)
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.