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Ex 5.2, 15 For what value of n, are the nth terms of two APs 63, 65, 67,… and 3, 10, 17, … equal Let’s find nth term of both APs 1st AP 63, 65, 67,… We know that an = a + (n – 1) d Here, a = 63 d = 65 – 63 = 2 Putting these in formula an = a + (n – 1) d = 63 + (n – 1) × 2 = 63 + 2n – 2 = 61 + 2n 2nd AP 3, 10, 17 … We know that an = a + (n – 1) d Here, a = 3 d = 10 – 3 = 7 Putting these in formula an = a + (n – 1) d = 3 + (n – 1) 7 = 3 + 7n – 7 = 7n – 4 Given that nth term of 1st AP = nth term of 2nd AP 61 + 2n = 7n – 4 61 + 4 = 7n – 2n 65 = 5n 65/5 = n 13 = n n = 13

Ex 5.2

Ex 5.2, 1

Ex 5.2, 2 (i) (MCQ)

Ex 5.2, 2 (ii) (MCQ) Important

Ex 5.2, 3 (i)

Ex 5.2, 3 (ii)

Ex 5.2, 3 (iii) Important

Ex 5.2, 3 (iv)

Ex 5.2, 3 (v) Important

Ex 5.2, 4

Ex 5.2, 5 (i)

Ex 5.2, 5 (ii) Important

Ex 5.2, 6 Important

Ex 5.2, 7

Ex 5.2, 8

Ex 5.2, 9

Ex 5.2, 10

Ex 5.2, 11

Ex 5.2, 12 Important

Ex 5.2, 13 Important

Ex 5.2, 14 Important

Ex 5.2, 15 You are here

Ex 5.2, 16

Ex 5.2, 17 Important

Ex 5.2, 18

Ex 5.2, 19

Ex 5.2, 20 Important

Chapter 5 Class 10 Arithmetic Progressions (Term 2)

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.