1. Chapter 5 Class 10 Arithmetic Progressions (Term 2)
  2. Serial order wise
  3. Ex 5.2

Ex 5.2, 10 - Chapter 5 Class 10 Arithmetic Progressions (Term 2)

Last updated at March 19, 2021 by

Ex 5.2, 10 - If 17th term of AP exceeds its 10th term by 7

Ex 5.2, 10 - Chapter 5 Class 10 Arithmetic Progressions - Part 2

  1. Chapter 5 Class 10 Arithmetic Progressions (Term 2)
  2. Serial order wise

    3. Ex 5.2

    Ex 5.3 →

Transcript

Ex 5.2, 10 If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference. We know that an = a + (n – 1) d So, a17 = a + (17 – 1) d a17 = a + 16d Also, a10 = a + (10 – 1)d a10 = a + 9d Given that 17th term of an A.P. exceeds its 10th term by 7 a17 – a10 = 7 (a + 16d) – (a + 9d) = 7 a + 16d – a – 9d = 7 a – a + 16d – 9d = 7 0 + 7d = 7 7d = 7 7d = 7 d = 7/7 d = 1 Therefore, common difference of the given AP is 1 (From (1) & (2))

Chapter 5 Class 10 Arithmetic Progressions (Term 2)
Serial order wise

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