1. Chapter 5 Class 10 Arithmetic Progressions
  2. Serial order wise
  3. Ex 5.2

Ex 5.2, 10 - Chapter 5 Class 10 Arithmetic Progressions

Last updated at Dec. 8, 2016 by

Ex 5.2, 10 - If 17th term of AP exceeds its 10th term by 7 - Ex 5.2

  1. Chapter 5 Class 10 Arithmetic Progressions
  2. Serial order wise

    3. Ex 5.2

    Ex 5.3 →

Transcript

Ex 5.2 ,10 If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference. We know that an = a + (n 1) d So, a17 = a + (17 1) d a17 = a + 16d Also, a10 = a + (10 1)d a10 = a + 9d Given that 17th term of an A.P. exceeds its 10th term by 7 a17 a10 = 7 (a + 16d) (a + 9d) = 7 a + 16d a 9d = 7 a a + 16d 9d = 7 0 + 7d = 7 7d = 7 7d = 7 d = 7/7 d = 1 Therefore, common difference of the given AP is 1

Chapter 5 Class 10 Arithmetic Progressions
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.