1. Chapter 5 Class 10 Arithmetic Progressions (Term 2)
  2. Serial order wise
  3. Ex 5.3

Ex 5.3, 5 - Chapter 5 Class 10 Arithmetic Progressions (Term 2)

Last updated at March 22, 2021 by

Ex 5.3, 5 - The first term of an AP is 5, last term is 45, sum is 400

Ex 5.3, 5 - Chapter 5 Class 10 Arithmetic Progressions - Part 2
Ex 5.3, 5 - Chapter 5 Class 10 Arithmetic Progressions - Part 3

  1. Chapter 5 Class 10 Arithmetic Progressions (Term 2)
  2. Serial order wise

    3. Ex 5.3

    Examples →

Transcript

Ex 5.3, 5 The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference. Given a = 5 , l = 45 & Sn = Sum = 400 Since last term is given, we can use formula Sn = ๐’/๐Ÿ (a + l) Putting values in formula 400 = ๐‘›/2 (5 + 45) 400 = ๐‘›/2 ร— 50 (400 ร— 2)/50 = n 8 ร— 2 = n 16 = n n = 16 So, Number of terms = 16 Finding d For d, we use the formula Sn = ๐’/๐Ÿ (2a + n โ€“ 1) d) Putting Sn = 400, n = 16, a = 5 400 = 16/2 (2 ร— 5 + (16 โ€“ 1)ร— d) 400 = 8 ร— (10 + 15d) 400/8 = 10 + 15d 50 = 10 + 15d 50 โ€“ 10 = 15d 40 = 15d 40/15 = d 8/3 = d d = ๐Ÿ–/๐Ÿ‘

Chapter 5 Class 10 Arithmetic Progressions (Term 2)
Serial order wise

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