# Ex 5.3, 5 - Chapter 5 Class 10 Arithmetic Progressions

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 5.3 ,5 The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference. Since last term is given, we can use formula Sn = ๐/2 (a + l) Here, a = 5 , l = 45 & Sn = Sum = 400 We need to find n Putting values in formula Sn = ๐/2 (a + l) 400 = ๐/2 (5 + 45) 400 = ๐/2 ร 50 (400 ร 2)/50 = n 8 ร 2 = n 16 = n 8 ร 2 = n 16 = n n = 16 So number of terms = 16 Now we need to find d For this we can use the formula Sn = ๐/2 (2a + n โ 1) d) 400 = 16/2 (2 ร 5 + (16 โ 1)ร d) 400 = 16/2 (10 + 15d) (400 ร 2)/16 = 10 + 15d 50 = 10 + 15d 50 โ 10 = 15d 40 = 15d 40/15 = d 8/3 = d d = 8/3

Chapter 5 Class 10 Arithmetic Progressions

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.