Ex 5.3, 3 - Chapter 5 Class 10 Arithmetic Progressions - Part 25

  1. Chapter 5 Class 10 Arithmetic Progressions (Term 2)
  2. Serial order wise

Transcript

Ex 5.3, 3 In an AP (x) Given ๐‘™ = 28, S = 144 and there are total 9 terms. Find a. Given ๐‘™ = 28 , S = 144 , n = 9 We can use formula Sn = ๐’/๐Ÿ (๐’‚+๐’) Putting Sn = 144, n = 9 & ๐‘™ = 28 144 = 9/2(๐‘Ž+28) (144 ร— 2)/9=๐‘Ž+28 32 =๐‘Ž+28 32 โ€“ 28 = a a = 4

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.